Proposition 3
Tag 09N0, permanent. Cite it as [Bourbaki, Tag 09N0].
Integration, chapter IX, § 1. Premeasures and measures on a topological space
*Let be a locally compact space, and let be a measure on . Denote by the mapping that associates to each compact subset of the induced measure . Then is a premeasure on , one has , and the linear mapping is a bijection of the space onto the space of premeasures on . Moreover, if is positive then .
It is clear that is a premeasure (Ch. V, §7, No. 2, Prop. 4) and that the mapping is linear. The relation means that induces the measure 0 on every compact set in ; then for , thus , which proves that is injective. It remains to prove that is surjective. Since every premeasure is a linear combination of positive premeasures, it will suffice to construct, for every positive premeasure , a positive measure such that . Let be a given function, and let be a compact set containing the support of ; the number is independent of the choice of , by the definition of induced measures, so that one can set ; then is a positive linear form on , that is, a positive measure. Let us verify that ; first, the relation extends to the case that is a finite upper semi-continuous function that is positive and is zero outside . For, let be a compact neighborhood of , and the (decreasing directed) set of continuous functions on , with support contained in , that are . Then (Ch. IV, §4, No. 4, Cor. 2 of Prop. 5)
and on the other hand since is zero on (Ch. V, §7, No. 1, Prop. 1). In particular, if is taken to be the extension by 0 of an element of , this formula shows that by the definition of induced measures, thus indeed .
If is positive, then
for every (Ch. V, §1, Def. 1 and §7, Prop. 1). The relation is obvious (Ch. IV, §5, No. 7, Lemma 3).
Q.E.D.
When is locally compact, we shall from now on identify the spaces and by means of the bijection .
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.