Bourbaki

Remark

Tag 0A6D, permanent. Cite it as [Bourbaki, Tag 0A6D].

Lie Groups and Lie Algebras, chapter II, § 6. The Hausdorff series

(2) Take gg to be the Lie algebra L^(X)\hat{L}(X). The group law introduced in the above proposition coincides with the law defined in no. 2. In other words,

ahb=H(a,b)for a,b in L^(X); a \mathbin{\mathbf{h}} b = H(a, b) \quad \text{for } a, b \text{ in } \hat{L}(X);
thus the Hausdorff group law is given by the Hausdorff series.

(3) Let gg be a Lie algebra with the integral filtration (Cng\mathscr{C}^n g) defined by the lower central series. Suppose that there exists m≥1m \geq 1 such that Cmg={0}\mathscr{C}^m g = \{0\}. With the topology derived from the filtration (Cng)n≥1(\mathscr{C}^n g)_{n \geq 1}, the Lie algebra gg is Hausdorff, complete and even discrete. Then P(a1,…,ar)=0P(a_1, \ldots, a_r) = 0 for a1,…,ara_1, \ldots, a_r in gg and for every homogeneous Lie polynomial PP of degree ≥m\geq m; in particular, Hr,s(a,b)=0H_{r,s}(a, b) = 0 for r+s≥mr + s \geq m and the series H(a,b)=∑r,sHr,s(a,b)H(a, b) = \sum_{r,s} H_{r,s}(a, b) has only a finite number of non-zero terms. The group law (a,b)↦H(a,b)(a, b) \mapsto H(a, b) on gg is then a polynomial mapping (§ 2, no. 4).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.