Let G be a real or complex Lie group and α *an infinitesimal automorphism of G. There exists a law of analytic operation (λ,g)↦ϕλ(g) of K on G with the following properties: (1) if D is the associated law of infinitesimal operation, then D(1)=α; (2) for all λ∈K, ϕλ∈AutG. (a) For all μ>0, let Kμ be the open ball of centre 0 and radius μ in K. For all g∈G, let Fg be the set of analytic integral curves f of α defined in a ball Kμ and such that f(0)=g. By Differentiable and Analytic Manifolds, R, 9.1.3 and 9.1.5, Fg is non-empty and two elements of Fg coincide on the intersection of their domains of definition; let μ(g) be the least upper bound of the numbers μ such that there exists an element of Fg defined in Kμ; there exists a unique element of Fg defined in Kμ(g); we denote it by fg. (b) Let g1,g2 be in G, f1∈Fg1,f2∈Fg2 with f1 and f2 defined on the same ball Kμ. Then f1f2:Kμ→G is analytic and (f1f2)(0)=g1g2. On the other hand, for all λ∈Kμ,
(Tλ(f1f2))1=(Tλf1)1⋅f2(λ)+f1(λ)⋅(Tλf2)1(§ 2, Proposition 7)
=α(f1(λ))f2(λ)+f1(λ)α(f2(λ))
=α((f1f2)(λ))(Lemma 1)
and hence f1f2∈Fg1g2. This proves that μ(g1g2)≥infg∈V(μ(g1),μ(g2)). (c) By Differentiable and Analytic Manifolds, R, 9.1.4 and 9.1.5, there exists a neighbourhood V of e in G such that σ=infg∈Vμ(g)>0. Let h∈G and C be its connected component. For all h′∈C, μ(h′)≥inf(σ,μ(h))>0 by (b). On the other hand, the functions fh′, where h′∈C, take their values in C. By Differentiable and Analytic Manifolds, R, 9.1.4 and 9.1.5, μ=+∞ in C and finally μ=+∞ in G. Then let fg(λ)=ϕλ(g) for all g∈G and all λ∈K. By Differentiable and Analytic Manifolds, R, 9.1.4 and 9.1.5, the mapping (λ,g)↦ϕλ(g) is a law of analytic operation of K on G. Clearly, if D is the associated law of infinitesimal operation, D(1)=α. By (b),
ϕλ(g1g2)=ϕλ(g1)ϕλ(g2)
for all λ∈K,g1∈G,g1∈G.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.