Bourbaki

Proposition 2

Tag 0ALA, permanent. Cite it as [Bourbaki, Tag 0ALA].

Lie Groups and Lie Algebras, chapter III, § 10. The automorphism group of a Lie group

Let G be a real or complex Lie group and α\alpha *an infinitesimal automorphism of G. There exists a law of analytic operation (λ,g)↦ϕλ(g)(\lambda, g) \mapsto \phi_\lambda(g) of K on G with the following properties: (1) if D is the associated law of infinitesimal operation, then D(1)=αD(1) = \alpha; (2) for all λ∈K\lambda \in K, ϕλ∈Aut G\phi_\lambda \in \mathrm{Aut}\, G. (a) For all μ>0\mu > 0, let KμK_\mu be the open ball of centre 0 and radius μ\mu in K. For all g∈Gg \in G, let Fg\mathscr{F}_g be the set of analytic integral curves ff of α\alpha defined in a ball KμK_\mu and such that f(0)=gf(0) = g. By Differentiable and Analytic Manifolds, R, 9.1.3 and 9.1.5, Fg\mathscr{F}_g is non-empty and two elements of Fg\mathscr{F}_g coincide on the intersection of their domains of definition; let μ(g)\mu(g) be the least upper bound of the numbers μ\mu such that there exists an element of Fg\mathscr{F}_g defined in KμK_\mu; there exists a unique element of Fg\mathscr{F}_g defined in Kμ(g)K_{\mu(g)}; we denote it by fgf_g. (b) Let g1,g2g_1, g_2 be in G, f1∈Fg1,f2∈Fg2f_1 \in \mathscr{F}_{g_1}, f_2 \in \mathscr{F}_{g_2} with f1f_1 and f2f_2 defined on the same ball KμK_\mu. Then f1f2:Kμ→Gf_1 f_2 : K_\mu \to G is analytic and (f1f2)(0)=g1g2(f_1 f_2)(0) = g_1 g_2. On the other hand, for all λ∈Kμ\lambda \in K_\mu,

(Tλ(f1f2))1=(Tλf1)1⋅f2(λ)+f1(λ)⋅(Tλf2)1(§ 2, Proposition 7) (T_\lambda(f_1 f_2))1 = (T_\lambda f_1)1 \cdot f_2(\lambda) + f_1(\lambda) \cdot (T_\lambda f_2)1 \quad (\S\ 2,\ \text{Proposition 7})
=α(f1(λ))f2(λ)+f1(λ)α(f2(λ)) = \alpha(f_1(\lambda)) f_2(\lambda) + f_1(\lambda) \alpha(f_2(\lambda))
=α((f1f2)(λ))(Lemma 1) = \alpha((f_1 f_2)(\lambda)) \tag{\text{Lemma 1}}

and hence f1f2∈Fg1g2f_1 f_2 \in \mathscr{F}_{g_1 g_2}. This proves that μ(g1g2)≥inf⁡g∈V(μ(g1),μ(g2))\mu(g_1 g_2) \geq \inf_{g \in V} (\mu(g_1), \mu(g_2)). (c) By Differentiable and Analytic Manifolds, R, 9.1.4 and 9.1.5, there exists a neighbourhood V of e in G such that σ=inf⁡g∈Vμ(g)>0\sigma = \inf_{g \in V} \mu(g) > 0. Let h∈Gh \in G and C be its connected component. For all h′∈Ch' \in C, μ(h′)≥inf⁡(σ,μ(h))>0\mu(h') \geq \inf(\sigma, \mu(h)) > 0 by (b). On the other hand, the functions fh′f_{h'}, where h′∈Ch' \in C, take their values in C. By Differentiable and Analytic Manifolds, R, 9.1.4 and 9.1.5, μ=+∞\mu = +\infty in C and finally μ=+∞\mu = +\infty in G. Then let fg(λ)=ϕλ(g)f_g(\lambda) = \phi_\lambda(g) for all g∈Gg \in G and all λ∈K\lambda \in K. By Differentiable and Analytic Manifolds, R, 9.1.4 and 9.1.5, the mapping (λ,g)↦ϕλ(g)(\lambda, g) \mapsto \phi_\lambda(g) is a law of analytic operation of K on G. Clearly, if D is the associated law of infinitesimal operation, D(1)=αD(1) = \alpha. By (b),

ϕλ(g1g2)=ϕλ(g1)ϕλ(g2) \phi_\lambda(g_1 g_2) = \phi_\lambda(g_1) \phi_\lambda(g_2)

for all λ∈K,g1∈G,g1∈G\lambda \in K, g_1 \in G, g_1 \in G.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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