Let M be the multiplicative group {1,−1}, and let m be an integer ≥2 (resp. m=∞). Then M acts on the group Z/mZ (resp. on Z) by (−1).x=−x, and the corresponding semi-direct product of M by Z/mZ (resp. of M by Z) is denoted by Dm. The elements of Dm are thus the pairs (ε,x) with ε=±1 and x∈Z/mZ (resp. x∈Z); the group law on Dm is given by the formula
(ε,x).(ε′,x′)=(εε′,ε′x+x′).
We denote by ι the class of 1 modulo m (resp. ι=1) and set
ρ=(−1,0),ρ′=(−1,ι),π=(1,ι).
Then ρ2=ρ′2=1 and π=ρρ′. The formulas
πn=(1,nι),ρπn=(−1,nι)
show that Dm is a dihedral group generated by {ρ,ρ′}.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.