Bourbaki

Example

Tag 0ALS, permanent. Cite it as [Bourbaki, Tag 0ALS].

Lie Groups and Lie Algebras, chapter IV, § 1. Coxeter Groups

Let MM be the multiplicative group {1,−1}\{1, -1\}, and let mm be an integer ≥2\geq 2 (resp. m=∞m = \infty). Then MM acts on the group Z/mZ\mathbf{Z}/m\mathbf{Z} (resp. on Z\mathbf{Z}) by (−1).x=−x(-1).x = -x, and the corresponding semi-direct product of MM by Z/mZ\mathbf{Z}/m\mathbf{Z} (resp. of MM by Z\mathbf{Z}) is denoted by DmD_m. The elements of DmD_m are thus the pairs (ε,x)(\varepsilon, x) with ε=±1\varepsilon = \pm 1 and x∈Z/mZx \in \mathbf{Z}/m\mathbf{Z} (resp. x∈Zx \in \mathbf{Z}); the group law on DmD_m is given by the formula

(ε,x).(ε′,x′)=(εε′,ε′x+x′). (\varepsilon, x).(\varepsilon', x') = (\varepsilon \varepsilon', \varepsilon' x + x').
We denote by ι\iota the class of 1 modulo mm (resp. ι=1\iota = 1) and set
ρ=(−1,0),ρ′=(−1,ι),π=(1,ι). \rho = (-1, 0), \quad \rho' = (-1, \iota), \quad \pi = (1, \iota).
Then ρ2=ρ′2=1\rho^2 = {\rho'}^2 = 1 and π=ρρ′\pi = \rho \rho'. The formulas
πn=(1,nι),ρπn=(−1,nι) \pi^n = (1, n\iota), \quad \rho \pi^n = (-1, n\iota)
show that DmD_m is a dihedral group generated by {ρ,ρ′}\{\rho, \rho'\}.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.