Bourbaki

Remark

Tag 0ALZ, permanent. Cite it as [Bourbaki, Tag 0ALZ].

Lie Groups and Lie Algebras, chapter IV, § 1. Coxeter Groups

Suppose that (W, S) is a Coxeter system. There exists a homomorphism ε\varepsilon from W to the group {1, -1} characterized by ε(s)=−1\varepsilon(s) = -1 for all s∈Ss \in S. We call ε(w)\varepsilon(w) the signature of w; it is equal to (−1)l(w)(-1)^{l(w)}. The formula ε(ww′)=ε(w)ε(w′)\varepsilon(ww') = \varepsilon(w)\varepsilon(w') thus translates into l(ww′)≡l(w)+l(w′)mod  2l(ww') \equiv l(w) + l(w') \mod 2.

¹ This means that (W, S) has the following universal property: given a group G and a map f from S to G such that (f(s)f(s′))m(s,s′)=1(f(s)f(s'))^{m(s,s')} = 1 for (s, s') in I, there exists a homomorphism g from W to G extending f. This homomorphism is unique because S generates W. An equivalent form of this definition is the following. Let W‾\overline{W} be a group, f a homomorphism from W‾\overline{W} to W and h a map from S to W‾\overline{W} such that f(h(s))=sf(h(s)) = s and (h(s)h(s′))m(s,s′)=1(h(s)h(s'))^{m(s,s')} = 1 for (s, s') in S and such that the h(s) (for s∈Ss \in S) generate W‾\overline{W}. Then f is injective (and hence is an isomorphism from W‾\overline{W} to W).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

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Transcribed from the printed volume. Not translated.