Bourbaki

Proposition 2

Tag 0AZ7, permanent. Cite it as [Bourbaki, Tag 0AZ7].

General Topology, chapter I, § 1. Open sets, neighbourhoods, closed sets

If to each element xx of a set XX there corresponds a set B(x)\mathfrak{B}(x) of subsets of XX such that the properties (VI), (V_{II}), (V_{III}) and (V_{IV}) are satisfied, then there is a unique topological structure on XX such that, for each x∈Xx \in X, B(x)\mathfrak{B}(x) is the set of neighbourhoods of xx in this topology.*

By Proposition 1, if there is a topology on XX satisfying these conditions, the set of open sets for this topology is necessarily the set D\mathscr{D} of subsets AA of XX such that for each x∈Ax \in A we have A∈B(x)A \in \mathfrak{B}(x); hence the uniqueness of this topology if it exists.

The set D\mathscr{D} certainly satisfies axioms (O_I) and (O_{II}): for (O_I), this follows immediately from (V_I), and for (O_{II}), from (V_{II}). It

!Diagram showing sets V, U, W, and points x, y, z

Figure 1.

remains to show that, in the topology defined by D\mathscr{D}, B(x)\mathfrak{B}(x) is the set of neighbourhoods of xx for each x∈Xx \in X. It follows from (V_I) that every neighbourhood of xx belongs to B(x)\mathfrak{B}(x). Conversely, let VV be a set belonging to B(x)\mathfrak{B}(x), and let UU be the set of points y∈Xy \in X such that V∈B(y)V \in \mathfrak{B}(y); if we can show that x∈U,U⊂Vx \in U, U \subset V and U∈DU \in \mathscr{D}, then the proof will be complete. We have x∈Ux \in U since V∈B(x)V \in \mathfrak{B}(x); also U⊂VU \subset V, for every point y∈Uy \in U belongs to VV by reason of (V_III) and the hypothesis V∈B(y)V \in \mathfrak{B}(y). It remains to show that U∈DU \in \mathscr{D}, i.e. that U∈B(y)U \in \mathfrak{B}(y) for each y∈Uy \in U; now (Fig. 1) if y∈Uy \in U then by (V_IV) there is a set WW such that for each z∈Wz \in W we have V∈B(z)V \in \mathfrak{B}(z); since V∈B(z)V \in \mathfrak{B}(z) means that z∈Uz \in U, it follows that W⊂UW \subset U, and therefore, by (V_I), that U∈B(y)U \in \mathfrak{B}(y).

Q.E.D.

Proposition 2 shows that a topology on XX can be defined by means of the sets B(x)\mathfrak{B}(x) of neighbourhoods of points of XX, subject only to the axioms (V_I), (V_II), (V_III) and (V_IV).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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