Remark 2
Tag 0BD0, permanent. Cite it as [Bourbaki, Tag 0BD0].
General Topology, chapter II, § 1. Uniform spaces
The conjunction of axioms (U_{II}) and (U_{III}) is equivalent (assuming the other axioms of uniform structures) to the following axiom:
(U_a) For each there exists such that (*).
Clearly (U_{II}) and (U_{III}) imply (U_a). Conversely, if (U_a) is satisfied we have , by (U_I); hence and therefore [by (F_1)] . Let ; then by what has just been proved and axiom (F_{II}), and we have .
Throughout this chapter we shall write instead of , and in general , for each integer and each subset of .
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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