Bourbaki

Example

Tag 0BF5, permanent. Cite it as [Bourbaki, Tag 0BF5].

General Topology, chapter II, § 3. Complete spaces

Suppose we are given in CC: (i) a sequence (an)(a_n) of distinct points such that the sequence (∣an∣)(|a_n|) is increasing and tends to +∞+\infty; (ii) for each nn, a rational function z→Rn(z)z \to R_n(z) defined in C−{an}C - \{a_n\} and having a pole at ana_n; (iii) an increasing sequence (Bn)(B_n) of open discs centred at 0, whose union is CC, and such that none of the aka_k is on the frontier of any of the discs BnB_n. For each nn, let Bn′B'_n denote the intersection of B‾n\overline{B}_n and the complement in CC of the set of points ana_n; and let XnX_n denote the set of all mappings

z→S(z)=P(z)+∑ak∈Bn′Rk(z) z \to S(z) = P(z) + \sum_{a_k \in B'_n} R_k(z)

of Bn′B'_n into CC, where PP is the restriction to Bn′B'_n of a function which is continuous in B‾n\overline{B}_n and holomorphic in BnB_n. We define a metric in XnX_n by putting

dn(S1,S2)=sup⁡z∈Bn′∣S1(z)−S2(z)∣. d_n(S_1, S_2) = \sup_{z \in B'_n} |S_1(z) - S_2(z)|.

It is easily verified that XnX_n is complete with respect to this metric. Finally, for n≤mn \leq m, we define a mapping fnm:Xm→Xnf_{nm} : X_m \to X_n such that if S∈XmS \in X_m then fnm(S)f_{nm}(S) is the restriction of SS to Bn′B'_n. It is clear that the fnmf_{nm} are uniformly continuous and that (Xn,fnm)(X_n, f_{nm}) is an inverse system of uniform spaces. This being so, an element of the inverse limit X=lim⁡←XnX = \lim_{\leftarrow} X_n can be canonically identified with a meromorphic function FF in C\mathbf{C}, whose only poles are the points ana_n, and which is such that for each nn, F(z)−Rn(z)F(z) - R_n(z) is holomorphic at ana_n. The classical theorem of Mittag-Leffler asserts that XX is not empty; by virtue of Theorem 1, we have only to verify the condition (MLnn_{nn}) for all nn. Let

Sn=Pn+∑ak∈BnRk S_n = P_n + \sum_{a_k \in B_n} R_k
be an element of XnX_n, where PnP_n is continuous in B‾n\overline{B}_n and holomorphic in BnB_n; for any m≥nm \geq n, let QmnQ_{mn} be the restriction of
∑ah∈Bm−BnRh to Bn′; \sum_{a_h \in B_m - B_n} R_h \text{ to } B'_n;
this latter sum is a holomorphic function in some neighbourhood of B‾n\overline{B}_n, hence (by Taylor's theorem) for each ε>0\varepsilon > 0 there is a polynomial PmnP_{mn} such that ∣Qmn(z)−Pmn(z)∣≤ε|Q_{mn}(z) - P_{mn}(z)| \leq \varepsilon in BnB_n; if SmS_m is the restriction of Sn+Qmn−PmnS_n + Q_{mn} - P_{mn} to Bm′B'_m, we have Sm∈XmS_m \in X_m and ∣Sm(z)−Sn(z)∣≤ε|S_m(z) - S_n(z)| \leq \varepsilon in Bn′B'_n. This completes the proof. \*

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed volume. Not translated.