The limit of the real-valued function M→supx∈Mf(x) with respect to the directed set G is called the upper limit of f with respect to the filter G, and is denoted by limsupGf, or by limsupx,Gf(x).
The lower limit of f with respect to the filter G is defined similarly, and is denoted by liminfGf or liminfx,Gf(x). Thus we have
{limsupGf=limM∈G(supx∈Mf(x)),liminfGf=limM∈G(infx∈Mf(x)).
(10)
Often the filter G is suppressed from the notation, and we write simply limsupf or limsupxf(x), or limsupf(x) when there is no risk of confusion.
From formulae (10) and Theorem 1 we have
x∈Xinff(x)≤limGinff≤limGsupf≤x∈Xsupf(x).
(11)
By Theorem 2 of no. 2 we may also write
{limsupGf=infM∈G(supx∈Mf(x)),liminfGf=supM∈G(infx∈Mf(x)).
(12)
Also we may replace the filter G, on the right-hand sides of formulae (10) and (12), by any base B of G.
From (2) and (10),
limGinff=−limGsup(−f)
and therefore we need consider only the upper limit.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
Nothing.