Bourbaki

Theorem 1

Tag 0BW0, permanent. Cite it as [Bourbaki, Tag 0BW0].

General Topology, chapter V, § 4. Exponentials and logarithms

The multiplicative group R+∗\mathbf{R}_+^* of real numbers >0> 0 is a topological group isomorphic to the additive group R\mathbf{R} of real numbers.

For R+∗=]0,+∞[\mathbf{R}_+^* = ]0, +\infty[ is an open interval of R\mathbf{R} and is therefore homeomorphic to R\mathbf{R} (Chapter IV, § 4, no. 1, Proposition 1). By Theorem 2 of § 3, it is therefore a topological group isomorphic to R\mathbf{R}.

From the Corollary to Proposition 5 of § 1, no. 3, for every number a>0a > 0 there is a unique continuous homomorphism faf_a of R\mathbf{R} into R+∗\mathbf{R}_+^* such that fa(1)=af_a(1) = a. Hence, for all x∈Rx \in \mathbf{R} and all y∈Ry \in \mathbf{R} we have

fa(x+y)=fa(x)fa(y),fa(−x)=1fa(x), f_a(x + y) = f_a(x) f_a(y), \qquad f_a(-x) = \frac{1}{f_a(x)},

and hence, in particular, for all n∈Zn \in \mathbf{Z},

fa(n)=an. f_a(n) = a^n.

For this reason we denote fa(x)f_a(x) by axa^x for all x∈Rx \in \mathbf{R}; the functions axa^x (for all values of a>0a > 0) are called exponential functions. We have 1x=11^x = 1 for all x∈Rx \in \mathbf{R}; if a≠1a \neq 1, x→axx \to a^x is an isomorphism of the group R\mathbf{R} onto the group R+∗\mathbf{R}_+^*.

If a≠1a \neq 1, the isomorphism of R+∗\mathbf{R}_+^* onto R\mathbf{R} which is the inverse of x→axx \to a^x is called the logarithm to base aa, and its value at x∈R+∗x \in \mathbf{R}_+^* is denoted by log⁡ax\log_a x. Thus, with this notation, we have

(1)

ax+y=axay(x∈R,y∈R,a>0); a^{x+y} = a^x a^y \qquad (x \in \mathbf{R}, y \in \mathbf{R}, a > 0);
(2)
a−x=1ax(x∈R,a>0); a^{-x} = \frac{1}{a^x} \qquad (x \in \mathbf{R}, a > 0);
(3)
log⁡a1=0,log⁡aa=1(a>0,a≠1); \log_a 1 = 0, \quad \log_a a = 1 \qquad (a > 0, a \neq 1);
(4)
log⁡a(xy)=log⁡ax+log⁡ay(x>0,y>0); \log_a (xy) = \log_a x + \log_a y \qquad (x > 0, y > 0);
(5)
log⁡a(1x)=−log⁡ax(x>0); \log_a \left( \frac{1}{x} \right) = -\log_a x \qquad (x > 0);
(6)
alog⁡ax=x(x>0); a^{\log_a x} = x \qquad (x > 0);
(7)
log⁡aax=x(x∈R). \log_a a^x = x \qquad (x \in \mathbf{R}).

By Proposition 5 of § 1, no. 3, every continuous homomorphism of R\mathbf{R} into R+∗\mathbf{R}_+^* is of the form y→axyy \to a^{xy}, where x∈Rx \in \mathbf{R}; since its value when y=1y = 1 is axa^x, we have identically

(8)

(ax)y=axy(x∈R, y∈R, a>0), (a^x)^y = a^{xy} \qquad (x \in \mathbf{R}, \ y \in \mathbf{R}, \ a > 0),
or, changing the notation,

(9)

xy=ay⋅log⁡ax(x>0,y∈R,a>0,a≠1). x^y = a^{y \cdot \log_a x} \qquad (x > 0, y \in \mathbf{R}, a > 0, a \neq 1).

The formula (8) shows that, for every integer n>0n > 0, we have (a1/n)n=a(a^{1/n})^n = a, which justifies the notation a1/na^{1/n} introduced for the nth root an\sqrt[n]{a}, defined in Chapter IV, § 3, no. 3.

Formulas (7) and (9) show that

(10)

log⁡a(xy)=ylog⁡ax(x>0,y∈R), \log_a (x^y) = y \log_a x \qquad (x > 0, y \in \mathbf{R}),
or, changing the notation,

(11)

log⁡ax=log⁡ab⋅log⁡bx(x>0,a>0,b>0,a≠1,b≠1), \log_a x = \log_a b \cdot \log_b x \qquad (x > 0, a > 0, b > 0, a \neq 1, b \neq 1),
which is the formula for "change of base".

Finally, let us obtain all the continuous homomorphisms of the topological group R∗\mathbf{R}^* into itself; if gg is such a continuous homomorphism,

log⁡a(g(ax)) \log_a (g(a^x))

is a continuous homomorphism of R\mathbf{R} into R\mathbf{R}, therefore (§ 1, no. 3, Proposition 5) there exists α∈R\alpha \in \mathbf{R} such that log⁡a(g(ax))=αx\log_a (g(a^x)) = \alpha x for all x∈Rx \in \mathbf{R}; hence, by (8), g(x)=xαg(x) = x^\alpha for all x>0x > 0. Hence we have identically

(12)

(xy)α=xαyα for all x>0,y>0 and α∈R. (xy)^\alpha = x^\alpha y^\alpha \text{ for all } x > 0, y > 0 \text{ and } \alpha \in \mathbf{R}.

By reason of formula (4), which reduces every multiplication to an addition (the only operation to which the customary system of numeration is well adapted), logarithms have long been an indispensable instrument in numerical calculations (see the Historical Note to this Chapter).

When used for this purpose, the base chosen is a=10a = 10; and there are tables giving the values of the function log⁡10x\log_{10} x (to a certain approximation). In analysis, one is led to choose a different base (denoted by ee) which is such that lim⁡x→1,x≠1log⁡ex(x−1)=1\lim_{x \to 1, x \neq 1} \frac{\log_e x}{(x - 1)} = 1 (cf. Exercise 1).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.