Bourbaki

Remark

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Commutative Algebra, chapter VIII, § 4. Séries de Hilbert-Samuel

The ring A((T))A((T)) is naturally identified with the ring of fractions A[[T]]TA[[T]]_T of the ring A[[T]]A[[T]] defined by the multiplicative subset formed by the powers of TT.

For n,pn, p in Z\mathbf{Z}, the natural number [np]\left[ \begin{array}{c} n \\ p \end{array} \right] is defined by

([np]=0if p<0 or p>n,[np]=(np)=n(n−1)...(n−p+1)p!if 0≤p≤n. \left( \begin{array}{ll} \left[ \begin{array}{c} n \\ p \end{array} \right] = 0 & \text{if } p < 0 \text{ or } p > n, \\ \left[ \begin{array}{c} n \\ p \end{array} \right] = \binom{n}{p} = \frac{n(n-1)...(n-p+1)}{p!} & \text{if } 0 \leq p \leq n . \end{array} \right.

One has [np]=[nn−p]\left[ \begin{array}{c} n \\ p \end{array} \right] = \left[ \begin{array}{c} n \\ n-p \end{array} \right] for n,p∈Zn, p \in \mathbf{Z}.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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