Let A be a ring, M an A-module and ( F n ) (F_n) ( F n ) a decreasing filtration on M consisting of submodules; suppose that there exists an integer n 1 n_1 n 1 such that F n 1 = M F_{n_1} = M F n 1 = M . Let f be an endomorphism of M, M ′ M' M ′ its kernel and M ′ ′ M'' M ′′ its cokernel. We equip M ′ M' M ′ with the filtration ( F n ′ ) (F'_n) ( F n ′ ) induced by ( F n ) (F_n) ( F n ) and M ′ ′ M'' M ′′ with the quotient filtration ( F n ′ ′ ) (F''_n) ( F n ′′ ) of ( F n ) (F_n) ( F n ) . Suppose that F n / F n + 1 F_n/F_{n+1} F n / F n + 1 is of finite length for every n ∈ Z n \in \mathbf{Z} n ∈ Z and that there exists an integer δ \delta δ such that f ( F n ) ⊂ F n + δ f(F_n) \subset F_{n+\delta} f ( F n ) ⊂ F n + δ . Let φ \varphi φ be the graded endomorphism of degree δ \delta δ of the graded module g r ( M ) = ⨁ n ∈ Z F n / F n + 1 \mathrm{gr}(M) = \bigoplus_{n \in \mathbf{Z}} F_n/F_{n+1} gr ( M ) = ⨁ n ∈ Z F n / F n + 1 deduced from f. Between the following elements of Z ( ( T ) ) \mathbf{Z}((T)) Z (( T ))
H M = ∑ n ∈ Z long A ( F n / F n + 1 ) . T n
H_M = \sum_{n \in \mathbf{Z}} \operatorname{long}_A(F_n/F_{n+1}).T^n
H M = n ∈ Z ∑ long A ( F n / F n + 1 ) . T n
H M ′ = ∑ n ∈ Z long A ( F n ′ / F n + 1 ′ ) . T n
H_{M'} = \sum_{n \in \mathbf{Z}} \operatorname{long}_A(F'_n/F'_{n+1}).T^n
H M ′ = n ∈ Z ∑ long A ( F n ′ / F n + 1 ′ ) . T n
H M ′ ′ = ∑ n ∈ Z long A ( F n ′ ′ / F n + 1 ′ ′ ) . T n
H_{M''} = \sum_{n \in \mathbf{Z}} \operatorname{long}_A(F''_n/F''_{n+1}).T^n
H M ′′ = n ∈ Z ∑ long A ( F n ′′ / F n + 1 ′′ ) . T n
P K e r ( φ ) = ∑ n ∈ Z long A ( K e r ( φ n ) ) . T n ,
P_{\mathrm{Ker}(\varphi)} = \sum_{n \in \mathbf{Z}} \operatorname{long}_A(\mathrm{Ker}(\varphi_n)).T^n ,
P Ker ( φ ) = n ∈ Z ∑ long A ( Ker ( φ n )) . T n ,
one has the inequalities
(17) H M ′ ≤ P K e r ( φ ) H_{M'} \leq P_{\mathrm{Ker}(\varphi)} H M ′ ≤ P Ker ( φ )
(18) ( 1 − T δ ) . H M ( 1 ) + T δ . P K e r ( φ ) ≤ H M ′ ′ ( 1 ) ≤ ( 1 − T δ ) . H M ( 1 ) + T δ . P K e r ( φ ) ( 1 ) (1 - T^\delta).H_M^{(1)} + T^\delta.P_{\mathrm{Ker}(\varphi)} \leq H_{M''}^{(1)} \leq (1 - T^\delta).H_M^{(1)} + T^\delta.P_{\mathrm{Ker}(\varphi)}^{(1)} ( 1 − T δ ) . H M ( 1 ) + T δ . P Ker ( φ ) ≤ H M ′′ ( 1 ) ≤ ( 1 − T δ ) . H M ( 1 ) + T δ . P Ker ( φ ) ( 1 ) .
The sequence of submodules G n = f − 1 ( F n + δ ) G_n = f^{-1}(F_{n+\delta}) G n = f − 1 ( F n + δ ) of M M M is a decreasing filtration, and one has F n ⊂ G n F_n \subset G_n F n ⊂ G n for every integer n n n . By definition, one has K e r ( φ n ) = ( G n + 1 ∩ F n ) / F n + 1 \mathrm{Ker}(\varphi_n) = (G_{n+1} \cap F_n)/F_{n+1} Ker ( φ n ) = ( G n + 1 ∩ F n ) / F n + 1 , whence
(19) P K e r ( φ ) = ∑ n ∈ Z l o n g A ( ( G n + 1 ∩ F n ) / F n + 1 ) . T n P_{\mathrm{Ker}(\varphi)} = \sum_{n \in \mathbf{Z}} \mathrm{long}_A((G_{n+1} \cap F_n)/F_{n+1}).T^n P Ker ( φ ) = ∑ n ∈ Z long A (( G n + 1 ∩ F n ) / F n + 1 ) . T n .
For every n n n , the A-module ( M ′ ∩ F n ) / ( M ′ ∩ F n + 1 ) (M' \cap F_n)/(M' \cap F_{n+1}) ( M ′ ∩ F n ) / ( M ′ ∩ F n + 1 ) identifies with a submodule of ( G n + 1 ∩ F n ) / F n + 1 (G_{n+1} \cap F_n)/F_{n+1} ( G n + 1 ∩ F n ) / F n + 1 , and inequality (17) follows at once from (19). By lemma 5, one has moreover
(20) P K e r ( φ ) ≤ ∑ n ∈ Z l o n g A ( G n + 1 / F n + 1 ) . T n ≤ P K e r ( φ ) ( 1 ) P_{\mathrm{Ker}(\varphi)} \leq \sum_{n \in \mathbf{Z}} \mathrm{long}_A(G_{n+1}/F_{n+1}).T^n \leq P_{\mathrm{Ker}(\varphi)}^{(1)} P Ker ( φ ) ≤ ∑ n ∈ Z long A ( G n + 1 / F n + 1 ) . T n ≤ P Ker ( φ ) ( 1 ) .
For every n ∈ Z n \in \mathbf{Z} n ∈ Z , one has an exact sequence of A-modules
0 ⟶ G n + 1 / F n + 1 ⟶ M / F n + 1 → f n M / F n + δ + 1 ⟶ M ′ ′ / F n + δ + 1 ′ ′ ⟶ 0 , 0 \longrightarrow G_{n+1}/F_{n+1} \longrightarrow M/F_{n+1} \xrightarrow{f_n} M/F_{n+\delta+1} \longrightarrow M''/F''_{n+\delta+1} \longrightarrow 0, 0 ⟶ G n + 1 / F n + 1 ⟶ M / F n + 1 f n M / F n + δ + 1 ⟶ M ′′ / F n + δ + 1 ′′ ⟶ 0 ,
where f n f_n f n is deduced from f f f by passing to quotients. Consequently one has
l o n g A ( M ′ ′ / F n + δ + 1 ′ ′ ) = l o n g A ( M / F n + δ + 1 ) − l o n g A ( M / F n + 1 ) + l o n g A ( G n + 1 / F n + 1 ) \mathrm{long}_A(M''/F''_{n+\delta+1}) = \mathrm{long}_A(M/F_{n+\delta+1}) - \mathrm{long}_A(M/F_{n+1}) + \mathrm{long}_A(G_{n+1}/F_{n+1}) long A ( M ′′ / F n + δ + 1 ′′ ) = long A ( M / F n + δ + 1 ) − long A ( M / F n + 1 ) + long A ( G n + 1 / F n + 1 ) .
Multiplying by T n + δ T^{n+\delta} T n + δ and summing over n n n , one obtains
(21) H M ′ ′ ( 1 ) = ( 1 − T δ ) H M ( 1 ) + T δ . ∑ n ∈ Z l o n g A ( G n + 1 / F n + 1 ) . T n , H_{M''}^{(1)} = (1 - T^\delta)H_M^{(1)} + T^\delta.\sum_{n \in \mathbf{Z}} \mathrm{long}_A(G_{n+1}/F_{n+1}).T^n, H M ′′ ( 1 ) = ( 1 − T δ ) H M ( 1 ) + T δ . ∑ n ∈ Z long A ( G n + 1 / F n + 1 ) . T n ,
and inequality (18) follows at once from (20) and (21).
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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