Bourbaki

Remark 5

Tag 0D07, permanent. Cite it as [Bourbaki, Tag 0D07].

Commutative Algebra, chapter X, § 1. Profondeur

Suppose that one has p=p′p = p' and that the injection u:M′→Mu : M' \to M which occurs in the exact sequence of prop. 1 belongs to JHom⁡A(M′,M)J \operatorname{Hom}_A(M', M). One then has p′′=p−1p'' = p - 1. In fact, the assumption implies that the mapping Ext⁡Ai(1A/J,u)\operatorname{Ext}_A^i(1_{A/J}, u) is zero for every integer ii; this excludes case a) considered above.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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