Proposition 1
Tag 0D6U, permanent. Cite it as [Bourbaki, Tag 0D6U].
Commutative Algebra, chapter X, § 5. Intersections complètes
Let be a ring, an ideal of , generated by a finite sequence of elements of . The following conditions are equivalent:
(i) the sequence is completely secant for ; (ii) (resp. (ii')) for every prime ideal (resp. maximal ideal) , the image of in is completely secant for ; (iii) (resp. (iii')) for every prime ideal (resp. maximal ideal) , the ideal is completely secant at and the image of in the -vector space forms a basis of it.
When is noetherian, these conditions are also equivalent to:
(iv) for every integer , the -module is free, and the images of the monomials of total degree form a basis of it.
Let be a prime ideal of ; let us denote by the image of the sequence in . For every integer , the -module is isomorphic to (A, X, p. 151, 2)) ; it is zero if does not contain , since then one has (A, X, p. 148, cor. 2). The equivalence of (i), (ii) and (ii') follows from this and from II, § 3, No. 3, cor. 2 of th. 1. On the other hand, the equivalence of (ii) and (iii), and that of (ii') and (iii'), follow from § 1, No. 3, cor. 2 of th. 1.
The implication (i) (iv) is a consequence of th. 1 of A, X, p. 160. Finally, condition (iv) implies by localization the analogous condition for the -modules for every , and the latter entails (ii) by cor. 1 of A, X, p. 160.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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