Lemma 5
Tag 0D9P, permanent. Cite it as [Bourbaki, Tag 0D9P].
Commutative Algebra, chapter X, § 7. Algèbres lisses
Let be a local homomorphism of noetherian local rings. Suppose that is essentially of finite type over . For the -algebra to be formally smooth, it is necessary and sufficient that the -module be flat and that the -algebra be absolutely regular.
There exists an integer , a prime ideal of , and a surjective homomorphism of onto . Let denote the local -algebra ; it is formally smooth (No. 3, Example 2 and No. 2, Prop. 4, a)) and flat over , and one can identify with the -algebra , where .
Put and . Suppose that is formally smooth over . Then the -algebra is formally smooth (No. 2, Prop. 4, b)), hence absolutely regular (No. 5, Cor. 2 of Th. 2). Moreover, since can be identified with and the -algebra is formally smooth, the ideal of is completely secant (No. 5, Th. 2). It then follows from § 5, No. 6, Prop. 6 that the -module is flat.
Suppose conversely that is flat over and that the -algebra is absolutely regular. Then the local -algebra is formally smooth (Remark 1 of No. 9 with ). Put ; since is a flat -module, the canonical mapping is bijective and can be identified with . It follows (Remark 1 of No. 2) that the canonical mapping
is injective and admits a retraction. Now is identified with , hence with ; on the other hand, the -module is canonically isomorphic to (A, III, p. 136, prop. 20), hence is canonically isomorphic to . Passing to the quotient by the maximal ideal of , one obtains an injective homomorphism
which is none other than . Thus B is formally smooth over A (th. 3).
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
Cited by
Nothing.
Cites
Nothing.