Bourbaki

Lemma 5

Tag 0D9P, permanent. Cite it as [Bourbaki, Tag 0D9P].

Commutative Algebra, chapter X, § 7. Algèbres lisses

Let ρ:A→B\rho : A \to B be a local homomorphism of noetherian local rings. Suppose that BB is essentially of finite type over AA. For the AA-algebra BB to be formally smooth, it is necessary and sufficient that the AA-module BB be flat and that the κA\kappa_A-algebra κA⊗AB\kappa_A \otimes_A B be absolutely regular.

There exists an integer n⩾0n \geqslant 0, a prime ideal qq of A[T1,…,Tn]A[T_1, \ldots, T_n], and a surjective homomorphism hh of A[T1,…,Tn]qA[T_1, \ldots, T_n]_q onto BB. Let CC denote the local AA-algebra A[T1,…,Tn]qA[T_1, \ldots, T_n]_q; it is formally smooth (No. 3, Example 2 and No. 2, Prop. 4, a)) and flat over AA, and one can identify BB with the AA-algebra C/JC/J, where J=Ker(h)J = \mathrm{Ker}(h).

Put C‾=κA⊗AC\overline{C} = \kappa_A \otimes_A C and B‾=κA⊗AB\overline{B} = \kappa_A \otimes_A B. Suppose that BB is formally smooth over AA. Then the κA\kappa_A-algebra B‾\overline{B} is formally smooth (No. 2, Prop. 4, b)), hence absolutely regular (No. 5, Cor. 2 of Th. 2). Moreover, since C‾/JC‾\overline{C}/J\overline{C} can be identified with B‾\overline{B} and the κA\kappa_A-algebra C‾\overline{C} is formally smooth, the ideal JC‾J\overline{C} of C‾\overline{C} is completely secant (No. 5, Th. 2). It then follows from § 5, No. 6, Prop. 6 that the AA-module BB is flat.

Suppose conversely that BB is flat over AA and that the κA\kappa_A-algebra B‾\overline{B} is absolutely regular. Then the local κA\kappa_A-algebra B‾\overline{B} is formally smooth (Remark 1 of No. 9 with k=k0=κAk = k_0 = \kappa_A). Put J‾=κA⊗AJ\overline{J} = \kappa_A \otimes_A J; since BB is a flat AA-module, the canonical mapping J‾→JC‾\overline{J} \to J\overline{C} is bijective and B‾\overline{B} can be identified with C‾/J‾\overline{C}/\overline{J}. It follows (Remark 1 of No. 2) that the canonical mapping

J‾/J‾2⟶B‾⊗C‾ΩκA(C‾) \overline{J}/\overline{J}^2 \longrightarrow \overline{B} \otimes_{\overline{C}} \Omega_{\kappa_A}(\overline{C})

is injective and admits a retraction. Now J‾/J‾2\overline{J}/\overline{J}^2 is identified with κA⊗AJ/J2\kappa_A \otimes_A J/J^2, hence with B‾⊗BJ/J2\overline{B} \otimes_B J/J^2; on the other hand, the C‾\overline{C}-module ΩκA(C‾)\Omega_{\kappa_A}(\overline{C}) is canonically isomorphic to C‾⊗CΩA(C)\overline{C} \otimes_C \Omega_A(C) (A, III, p. 136, prop. 20), hence B‾⊗C‾ΩκA(C‾)\overline{B} \otimes_{\overline{C}} \Omega_{\kappa_A}(\overline{C}) is canonically isomorphic to B‾⊗CΩA(C)\overline{B} \otimes_C \Omega_A(C). Passing to the quotient by the maximal ideal of B‾\overline{B}, one obtains an injective homomorphism

κB⊗BJ/J2⟶κB⊗CΩA(C) \kappa_B \otimes_B J/J^2 \longrightarrow \kappa_B \otimes_C \Omega_A(C)

which is none other than dκBd_{\kappa_B}. Thus B is formally smooth over A (th. 3).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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