Bourbaki

Definition 4

Tag 0DIT, permanent. Cite it as [Bourbaki, Tag 0DIT].

Algebra, chapter IX, § 1. Formes sesquilinéaires

We say that a mapping Φ\Phi of E×FE \times F into G is right sesquilinear for J if it satisfies conditions (1), (2), (3) (def. 1, No. 1) as well as (7) Φ(x,by)=Φ(x,y)⋅bJ\Phi(x, by) = \Phi(x, y) \cdot b^J for all x∈E, y∈Fx \in E,\ y \in F and b∈Bb \in B.

If J is the identity (which requires that B be commutative), we recover the notion of a bilinear mapping.

Let (ei)i∈I(e_i)_{i \in I} and (fk)k∈K(f_k)_{k \in K} be two families of elements of E and F, and let (ai)i∈I(a_i)_{i \in I} and (bk)k∈K(b_k)_{k \in K} be elements of A and B which are zero except for a finite number of them. Then

Φ(∑iaiei,∑kbkfk)=∑i,kaiΦ(ei,fk)bkJ. \Phi(\sum_i a_i e_i, \sum_k b_k f_k) = \sum_{i,k} a_i \Phi(e_i, f_k) b_k^J.

As in the case of a bilinear mapping, the elements Φ(ei,fk)\Phi(e_i, f_k) determine Φ\Phi uniquely when (ei)(e_i) and (fk)(f_k) are generating systems, and may be chosen arbitrarily when (ei)(e_i) and (fk)(f_k) are bases of E and F; when (ei)(e_i) and (fk)(f_k) are finite bases, (Φ(ei,fk))(\Phi(e_i, f_k)) is called the matrix of Φ\Phi with respect to these bases.

As for bilinear mappings, one defines on the set of right sesquilinear mappings (for JJ) from E×FE \times F into GG a bimodule structure over the centres of AA and BB. One defines the notion of inverse image of a sesquilinear mapping by the same formula as for a bilinear mapping. We shall moreover see that the study of sesquilinear mappings can be reduced to that of bilinear mappings.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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