Bourbaki

Definition 6

Tag 0DIW, permanent. Cite it as [Bourbaki, Tag 0DIW].

Algebra, chapter IX, § 1. Formes sesquilinéaires

Two elements x∈Ex \in E and y∈Fy \in F are said to be orthogonal with respect to Φ\Phi if Φ(x,y)=0\Phi(x, y) = 0. Two subsets E′⊂EE' \subset E and F′⊂FF' \subset F are said to be orthogonal if, whatever x∈E′x \in E' and y∈F′y \in F', xx and yy are orthogonal. The set of elements of EE (resp. F) orthogonal to a given submodule N of F (resp. M of E) is a submodule of E (resp. F), called the totally orthogonal submodule (or simply orthogonal submodule) to N (resp. M), and denoted by N0N^0 (resp. M0M^0).

Let H and H′H' be two submodules of E or F. We have H⊂(H0)0H \subset (H^0)^0 (denoted by H00H^{00}); if H⊂H′H \subset H', we have H′0⊃H0{H'}^0 \supset H^0. It follows that we have H0⊃(H00)0H^0 \supset (H^{00})^0 and H0⊂(H0)00H^0 \subset (H^0)^{00}; on putting

H000=(H00)0=(H0)00=((H0)0)0, H^{000} = (H^{00})^0 = (H^0)^{00} = ((H^0)^0)^0,

we therefore have H0=H000H^0 = H^{000}.

For the mapping Φ\Phi to be degenerate (No. 1, Def. 3), it is necessary and sufficient that at least one of the two submodules E0,F0E^0, F^0 be ≠{0}\neq \{0\}. It is clear that Φ(x,y)\Phi(x, y) does not change when an element of F0F^0 (resp. E0E^0) is added to xx (resp. yy), and Φ\Phi therefore defines by passing to the quotient a bilinear mapping (or sesquilinear mapping) on (E/F0)×(F/E0)(E/F^0) \times (F/E^0); this is plainly non-degenerate; it is called the non-degenerate bilinear mapping (or sesquilinear mapping) associated with Φ\Phi.

Let (Ei)i∈I(E_i)_{i \in I} be a family of left A-modules, (Fi)i∈I(F_i)_{i \in I} a family of right B-modules (resp. left B-modules), and Φi\Phi_i a bilinear (resp. right J-sesquilinear) mapping of Ei×FiE_i \times F_i into G. Let EE (resp. FF) denote the direct sum module of the EiE_i (resp. FiF_i). It is immediately seen that the mapping Φ\Phi of E×FE \times F into G defined by

Φ((xi),(yi))=∑iΦi(xi,yi)(xi∈Ei,yi∈Fi) \Phi((x_i), (y_i)) = \sum_i \Phi_i(x_i, y_i) \quad (x_i \in E_i, y_i \in F_i)
(the sum having a meaning since all but a finite number of its terms are zero) is bilinear (resp. right J-sesquilinear). It is called the direct sum of the mappings Φi\Phi_i. It is clear that EiE_i is orthogonal to FjF_j with respect to Φ\Phi for i≠ji \neq j. Conversely, let Φ\Phi be a bilinear or sesquilinear mapping of E×FE \times F into G, and suppose that E is the direct sum of submodules (Ei)i∈I(E_i)_{i \in I} and F the direct sum of submodules (Fi)i∈I(F_i)_{i \in I} such that EiE_i is orthogonal to FjF_j for i≠ji \neq j; then Φ\Phi is the direct sum of its restrictions to the products Ei×FiE_i \times F_i (i∈Ii \in I).

For Φ\Phi to be non-degenerate, it is necessary and sufficient that each of the Φi\Phi_i be so; under these conditions, the submodule orthogonal to EiE_i is ∑j≠iFj\sum_{j \neq i} F_j.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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