Bourbaki

Definition 11

Tag 0DJJ, permanent. Cite it as [Bourbaki, Tag 0DJJ].

Algebra, chapter IX, § 1. Formes sesquilinéaires

Given A-modules Ei,Fi(i=1,…,m)E_i, F_i (i = 1, \ldots, m) and, for each ii, a sesquilinear form Φi\Phi_i for JJ on Ei×FiE_i \times F_i, the sesquilinear form Φ\Phi for JJ on (⨂iEi)×(⨂iFi)(\bigotimes_i E_i) \times (\bigotimes_i F_i) characterized by (35) is called the tensor product of the sesquilinear forms Φi\Phi_i.

In the case where the EiE_i and the FiF_i are equal to one and the same module EE, and where the Φi\Phi_i are equal to one and the same form Ψ\Psi, we say that Φ\Phi is the extension of Ψ\Psi to ⨂mE\bigotimes^m E.

With the notations of Def. 11, let us study the mappings associated with Φ\Phi. From formula (24) (No. 6) and from (35) one obtains the relation

Φ(x1⊗⋯⊗xm,y1⊗⋯⊗ym)=∏i=1m⟨xi,dΦi(yi)⟩=∏i=1m⟨yi,sΦi(xi)⟩J. \Phi(x_1 \otimes \cdots \otimes x_m, y_1 \otimes \cdots \otimes y_m) = \prod_{i=1}^m \langle x_i, d_{\Phi_i}(y_i) \rangle = \prod_{i=1}^m \langle y_i, s_{\Phi_i}(x_i) \rangle^J.

We have therefore:

(36) sΦ=js∘(sΦ1⊗⋯⊗sΦm),dΦ=jd∘(dΦ1⊗⋯⊗dΦm)s_\Phi = j_s \circ (s_{\Phi_1} \otimes \cdots \otimes s_{\Phi_m}), \quad d_\Phi = j_d \circ (d_{\Phi_1} \otimes \cdots \otimes d_{\Phi_m})

where jsj_s (resp. jdj_d) denotes the canonical mapping of ⨂iFi∗\bigotimes_i F_i^* into (⨂iFi)∗(\bigotimes_i F_i)^* (resp. of ⨂iEi∗\bigotimes_i E_i^* into (⨂iEi)∗(\bigotimes_i E_i)^*) (Chap. III, § 1, Nos. 4 and 7).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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