Bourbaki

Proposition 4

Tag 0DLO, permanent. Cite it as [Bourbaki, Tag 0DLO].

Algebra, chapter IX, § 6. Propriétés spéciales aux formes hermitiennes

Let u ∈ GL(E) be an involution. The following properties are equivalent: a) u belongs to the unitary group associated with Φ ; b) the submodules U^+ = 12(1+u)(E)\frac{1}{2}(1 + u)(E) and U^- = 12(1−u)(E)\frac{1}{2}(1 - u)(E) are orthogonal (and consequently non-isotropic). Moreover, if A is a field and E is finite-dimensional, properties a) and b) are equivalent to: c) u = u*. Indeed, for x ∈ U^+ and y ∈ U^-, the relation Φ(u(x),u(y))=Φ(x,y)\Phi(u(x), u(y)) = \Phi(x, y) gives 2Φ(x,y)=02\Phi(x, y) = 0, hence a) implies b). Conversely, we obviously have Φ(u(x),u(y))=Φ(x,y)\Phi(u(x), u(y)) = \Phi(x, y) when x and y both belong to U^+ or both belong to U^-, and, in view of b), this relation is still true when one of them belongs to U^+ and the other to U^-; since E is the direct sum of U^+ and U^-, we see that b) implies a). Finally, when E is a finite-dimensional vector space, the adjoint u* is defined since Φ is non-degenerate; relation a) is equivalent to uu∗=1uu^* = 1 (§ 1, No. 8, cor. of prop. 8); since u2=1u^2 = 1 by assumption, a) and c) are equivalent.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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