Let us write O+ additively. For every pair of elements θ,θ′ of O+ one has
(3)
c(θ)2−δs(θ)2=1
(4)
c(θ+θ′)=c(θ)c(θ′)+δs(θ)s(θ′)
(5)
s(θ+θ′)=s(θ)c(θ′)+c(θ)s(θ′).
Relation (3) expresses in fact that N(c(θ)+s(θ)ω)=1. For (4) and (5) it is enough to calculate, in A(Φ), the product of the rotations c(θ)+s(θ)ω and c(θ′)+s(θ′)ω.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.