Bourbaki

Proposition 5

Tag 0DOC, permanent. Cite it as [Bourbaki, Tag 0DOC].

Algebra, chapter IX, § 10. Angles

Let us write O+O^+ additively. For every pair of elements θ,θ′\theta, \theta' of O+O^+ one has

(3)

c(θ)2−δs(θ)2=1 c(\theta)^2 - \delta s(\theta)^2 = 1
(4)
c(θ+θ′)=c(θ)c(θ′)+δs(θ)s(θ′) c(\theta + \theta') = c(\theta)c(\theta') + \delta s(\theta)s(\theta')
(5)
s(θ+θ′)=s(θ)c(θ′)+c(θ)s(θ′). s(\theta + \theta') = s(\theta)c(\theta') + c(\theta)s(\theta').

Relation (3) expresses in fact that N(c(θ)+s(θ)ω)=1N(c(\theta) + s(\theta)\omega) = 1. For (4) and (5) it is enough to calculate, in A(Φ)A(\Phi), the product of the rotations c(θ)+s(θ)ωc(\theta) + s(\theta)\omega and c(θ′)+s(θ′)ωc(\theta') + s(\theta')\omega.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

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Translated with machine help, not yet reviewed by a person.