Bourbaki

Remark 2

Tag 0DOK, permanent. Cite it as [Bourbaki, Tag 0DOK].

Algebra, chapter IX, § 10. Angles

In the definition of the group of angles of lines, one may, instead of the group S+/HS^+/H, use the group O+/{−1,1}O^+/ \{ -1, 1 \} which is canonically isomorphic to it (Prop. 7). The canonical homomorphism of O+O^+ onto O+/{−1,1}O^+/ \{ -1, 1 \} thus corresponds to a homomorphism of A\mathfrak{A} onto A0\mathfrak{A}_0, namely the one which associates with the angle of the two half-lines Δ,Δ′\Delta, \Delta' the angle of the lines D,D′D, D' containing respectively Δ,Δ′\Delta, \Delta'. In the case where the field A is the field of real numbers, the group A\mathfrak{A} is thus a covering of order 2 of the group A0\mathfrak{A}_0

According to Prop. 8, all angles of lines (resp. half-lines) of the form (D′,D′′^)(\widehat{D', D''}) where D′D' and D′′D'' are orthogonal (resp.

of the form (D,−D^\widehat{D, - D}) are equal: this follows in fact from Remark 2 of No. 1 (resp. is obvious). This angle of lines (resp. of half-lines) is called the right angle (resp. the flat angle); it is an element of order 2 of A0\mathfrak{A}_0 (resp. of A\mathfrak{A}).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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