Bourbaki

Remark 4

Tag 0DOQ, permanent. Cite it as [Bourbaki, Tag 0DOQ].

Algebra, chapter IX, § 10. Angles

Let FF be a vector space of arbitrary dimension over the maximal ordered field A\mathbf{A}, and let Ψ\Psi be a positive non-degenerate symmetric bilinear form on FF. Given two linearly independent vectors x,yx, y of FF, let F′F' be the vector plane which they generate; the angle of xx and yy is defined to be the angle of xx and yy considered as elements of the plane F′F'; it is denoted by (x,y^)(\widehat{x, y}). The cosine of this angle is, by virtue of (19), given by

cos⁡(x,y^)=Ψ(x,y)/∣x∣.∣y∣ \cos (\widehat{x, y}) = \Psi(x, y)/|x|.|y|

(where ∣x∣=Ψ(x,x)1/2|x| = \Psi(x, x)^{1/2} is also called the length of the vector xx), and is therefore independent of the orientation chosen on F′F'; the sine and the tangent of (x,y^)(\widehat{x, y}) change sign if one changes the orientation of F′F'. Given two non-zero proportional vectors x,yx, y of FF, one sets (x,y^)=0(\widehat{x, y}) = 0 by convention.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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