Bourbaki

Proposition 11

Tag 0DOR, permanent. Cite it as [Bourbaki, Tag 0DOR].

Algebra, chapter IX, § 10. Angles

Let E be an oriented plane over an ordered field A, D₀ a half-line of E, and G the set of half-lines of E distinct from D₀. The relation

“D₁ = D₂, or the sequence D₀, D₁, D₂ is direct”

between elements D₁, D₂ of G is a total ordering relation in G.

Indeed the axioms for total ordering relations are verified trivially, with the exception of transitivity. Let D₁, D₂, D₃ be three half-lines such that the sequences D₀, D₁, D₂ and D₀, D₂, D₃ are direct; we shall now prove that the sequence D₀, D₁, D₃ is direct. For this let us take a vector xᵢ ≠ 0 in Dᵢ (i = 0, 1, 2, 3), choose a bivector e > 0, and set xᵢ ∧ xⱼ = aᵢⱼe (aᵢⱼ ∈ A). Writing e = x₀ ∧ y (y ∈ E), and taking (x₀, y) as a basis of E, one easily verifies the relation

a01a23+a02a31+a03a12=0. a_{01}a_{23} + a_{02}a_{31} + a_{03}a_{12} = 0.

This being so, if a₀₁ ≤ 0, one has a₁₂ > 0 and a₂₀ > 0 (since the first sequence is direct), then a₂₃ > 0 and a₃₀ > 0 (since a₀₂ < 0 and the second sequence is direct), whence a₁₃ > 0 (by virtue of (22)); therefore the sequence (D₀, D₁, D₃) is direct in this case. Suppose henceforth that a₀₁ > 0. If a₃₀ ≤ 0, one has a₀₂ > 0 and a₂₃ > 0 (since the second sequence is direct), then a₁₂ > 0 (since a₂₀ < 0 and the first sequence is direct), whence a13>0a_{13} > 0 (by (22)), and the sequence (D0,D1,D3)(D_0, D_1, D_3) is direct. Finally it is obviously analogous if a01>0a_{01} > 0 and a30>0a_{30} > 0. QED.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

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