Bourbaki

Corollary

Tag 0DOS, permanent. Cite it as [Bourbaki, Tag 0DOS].

Algebra, chapter IX, § 10. Angles

*Let D1D_1 and D2D_2 be two distinct half-lines of E. For every half-line D0D_0 of E such that the sequence D0,D1,D2D_0, D_1, D_2 is direct, the set of half-lines DD of E such that D1<D<D2D_1 < D < D_2 (for the total ordering relation defined by D0D_0) is equal to the open angular sector with origin D1D_1 and extremity D2D_2.

Indeed, given a half-line D3D_3, it is a question of proving that the relations “the sequence D1,D3,D2D_1, D_3, D_2 is direct” and “the sequences D0,D1,D3D_0, D_1, D_3 and D0,D3,D2D_0, D_3, D_2 are direct” are equivalent. For brevity let us denote by (ijk)(ijk) the relation “the sequence (Di,Dj,Dk)(D_i, D_j, D_k) is direct”. By prop. 11, the conjunction of (132) and (120) implies (130); analogously the conjunction of (201) and (213) implies (203); whence one half of our assertion. Conversely suppose (012), (013), and (032); since the conjunction of (312) and (320) implies (310) (prop. 11), and since (310) and (013) are incompatible, (312) is false; this proves (132) and completes the proof.

By virtue of the preceding corollary, the open (resp. closed) angular sector with origin D1D_1 and extremity D2D_2 is denoted by {D1,D2}\{D_1, D_2\} (resp. [D1,D2][D_1, D_2]), it being understood that these are intervals for the order structure defined by any half-line D0D_0 such that the sequence D0,D1,D2D_0, D_1, D_2 is direct.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

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