Bourbaki

Proposition 12

Tag 0DOT, permanent. Cite it as [Bourbaki, Tag 0DOT].

Algebra, chapter IX, § 10. Angles

*Let A be a maximal ordered field, E an oriented plane over A, D0D_0 a half-line of E, and G the set of half-lines of E distinct from D0D_0. The totally ordered sets A and G (prop. 11) are isomorphic.

Let, indeed, (x,y)(x, y) be a basis of E such that x∈−D0x \in - D_0 and the bivector x∧yx \wedge y be >0> 0. To every element tt of A let us correspond the half-line f(t)f(t) to which the vector (1−t2)x+2ty(1 - t^2)x + 2ty. It is clear that f(A)⊂Gf(A) \subset G. Let us prove that ff is strictly increasing. Indeed, in order that the sequence D0,f(t),f(t′)D_0, f(t), f(t') (t,t′t, t' in A) be direct, it is necessary and sufficient, by definition, that at least two of the elements

−2t,(1−t2)2t′−(1−t′2)2t,2t′ -2t, \quad (1-t^2)2t' - (1-{t'}^2)2t, \quad 2t'

let them be >0> 0. Now the second is equal to 2(t′−t)(1+tt′)2(t' - t)(1 + tt'). Hence, if t<t′t < t', then either tt′⩾0tt' \geqslant 0, whence t′>0t' > 0 or −t>0-t > 0, or tt′<0tt' < 0, whence −t>0-t > 0 and t′>0t' > 0; in any case D0,f(t),f(t′)D_0, f(t), f(t') is direct. Since AA is totally ordered, ff is an isomorphism of AA onto the ordered set f(A)f(A) (Ens, Chapter III, § 1, No. 14, Prop. 13).

It remains to prove that ff is surjective. For this, consider the positive form Φ\Phi on EE such that (x,y)(x, y) is an orthonormal basis for Φ\Phi. For every half-line D∈GD \in G, there exists an angle φ\varphi and only one such that 2φ=(−D0,D^)2\varphi = (\widehat{-D_0, D}) (No. 1, Prop. 3); since (−D0,D^)(\widehat{-D_0, D}) is not the straight angle, φ\varphi is not the right angle, and tg⁡φ\operatorname{tg} \varphi is therefore finite. Then, by virtue of formulas (16) (No. 3), we have D=f(tg⁡φ)D = f(\operatorname{tg} \varphi). This completes the proof.

Exercises. 1) With the notation of No. 1, put Q(x)=Φ(x,x)Q(x) = \Phi(x, x); the vector space EE is canonically identified with C−(Q)C^-(Q) (§ 9, No. 1). For every z∈C+(Q)z \in C^+(Q), and every x∈Ex \in E, we have zx∈Ezx \in E; prove that x→zxx \to zx is an element of A(Φ)A(\Phi), and that z→szz \to s_z is an isomorphism of C+(Q)C^+(Q) onto the algebra A(Φ)A(\Phi).

2) The hypotheses and notation are those of No. 1 and of Exercise 1.

a) Let CC be the set of x∈Ex \in E such that Φ(x,x)=1\Phi(x, x) = 1 (unit circle), and let D\mathscr{D} be the set of lines DD whose intersection with CC is not empty (and consequently consists of two opposite elements of EE). A pointed line is, by definition, any pair Δ=(D,z)\Delta = (D, z) formed of a line D∈DD \in \mathscr{D} and one of the points z∈D∩Cz \in D \cap C. Now prove that if Δ1=(D1,z1)\Delta_1 = (D_1, z_1), Δ2=(D2,z2)\Delta_2 = (D_2, z_2) are two pointed lines, there exists one and only one rotation uu such that u(z1)=z2u(z_1) = z_2 (and consequently u(D1)=D2u(D_1) = D_2), which is expressed by writing u(Δ1)=Δ2u(\Delta_1) = \Delta_2. In the set of pairs (Δ1,Δ2)(\Delta_1, \Delta_2) of pointed lines, the relation “there exists a rotation uu such that u(Δ1)=Δ1′u(\Delta_1) = \Delta_1' and u(Δ2)=Δ2′u(\Delta_2) = \Delta_2'” is an equivalence relation. The set U1\mathfrak{U}_1 of equivalence classes of pairs of pointed lines with respect to this relation is called the set of angles of pointed lines, and the equivalence class to which a pair (Δ1,Δ2)(\Delta_1, \Delta_2) of pointed lines belongs is called the angle of this pair and denoted by (Δ1,Δ2^)(\widehat{\Delta_1, \Delta_2}); the relation (Δ1,Δ2^)=(Δ1′,Δ2′^)(\widehat{\Delta_1, \Delta_2}) = (\widehat{\Delta_1', \Delta_2'}) is equivalent to (Δ1,Δ1′^)=(Δ2,Δ2′^)(\widehat{\Delta_1, \Delta_1'}) = (\widehat{\Delta_2, \Delta_2'}) and the rotation which transforms Δ1\Delta_1 into Δ2\Delta_2 is said to be a rotation of angle 0=(Δ1,Δ2^)0 = (\widehat{\Delta_1, \Delta_2}) and is denoted by h1(θ)h_1(\theta); h1h_1 is a bijection of U1\mathfrak{U}_1 onto O+O^+, and the commutative group structure of O+O^+ is transported to U1\mathfrak{U}_1 by means of h1−1h_1^{-1}, the group U1\mathfrak{U}_1 thus defined being written additively; the angle of the pair formed by a pointed line (D,z)(D, z) and the “opposite” pointed line (D,−z)(D, -z), corresponding to the rotation x→−xx \to -x, is again called the flat angle in U1\mathfrak{U}_1.

b) In the set D0⊃D\mathscr{D}_0 \supset \mathscr{D} of non-isotropic lines, one defines as in No. 3 the notion of angle of lines, the group U0\mathfrak{U}_0 (using Corollary 3 of Proposition 1 of No. 1), the right angle in U0\mathfrak{U}_0, and the canonical bijection hh of U0\mathfrak{U}_0 onto S+/HS^+/H. With the notation of the corollary of Proposition 3, put dˉ=h1−1∘d∘h\bar{d} = h_1^{-1} \circ d \circ h and iˉ=h−1∘i∘h1\bar{i} = h^{-1} \circ i \circ h_1, so that iˉ\bar{i} is a homomorphism of U1\mathfrak{U}_1 into U0\mathfrak{U}_0 and dˉ\bar{d} a homomorphism of U0\mathfrak{U}_0 into U1\mathfrak{U}_1; dˉ\bar{d} is bijective, and the kernel of iˉ\bar{i} consists of '0 and the flat angle; moreover one has dˉ(iˉ(θ))=2θ\bar{d}(\bar{i}(\theta)) = 2\theta for θ∈U1\theta \in \mathfrak{U}_1 and iˉ(dˉ(φ))=2φ\bar{i}(\bar{d}(\varphi)) = 2\varphi for φ∈U0\varphi \in \mathfrak{U}_0. In order that iˉ\bar{i} be surjective (in other words, in order that D\mathscr{D} be the set of all non-isotropic lines), it is necessary and sufficient that the field A be Pythagorean (Chapter VI, § 2, Exercise 8 d)) and that there exist an orthonormal basis for Φ\Phi; this comes to the same as saying that Φ(x,x)\Phi(x, x) is a square for every x∈Ex \in E.

3) The hypotheses and notation are those of Exercise 2. a) Let s be a symmetry with respect to a non-isotropic line D (§6§ 6, No. 4). For every pointed line Δ1=(D1,z1)\Delta_1 = (D_1, z_1), let

Δ2=s(Δ1)=(s(D1),s(z1)), \Delta_2 = s(\Delta_1) = (s(D_1), s(z_1)),
and let φ=(D1^,D^)\varphi = (\widehat{D_1}, \widehat{D}); now prove that one has (Δ1^,Δ2^)=dˉ(φ)(\widehat{\Delta_1}, \widehat{\Delta_2}) = \bar{d}(\varphi). b) Now prove that every orthogonal transform of determinant -1 is a symmetry s with respect to a non-isotropic line (cf. § 6, Exercise 15 e)); for every rotation u, one has sus−1=u−1sus^{-1} = u^{-1}. c) If x,yx, y are any two points of E such that Φ(x,x)=Φ(y,y)≠0\Phi(x, x) = \Phi(y, y) \neq 0, there exists one and only one symmetry with respect to a non-isotropic line, which transforms xx into yy. d) Let s, s' be the symmetries with respect to two non-isotropic lines D, D', and let φ=(D^,D′^)\varphi = (\widehat{D}, \widehat{D'}); in order that s’s be a rotation of angle θ\theta, it is necessary and sufficient that dˉ(φ)=θ\bar{d}(\varphi) = \theta. e) Now prove that the commutator subgroup of the orthogonal group O(Q) is the image of U1\mathfrak{U}_1 under the homomorphism θ→h1(2θ)\theta \to h_1(2\theta) (§6§ 6, Exercise 17 a)); in order that this image be equal to O+O^+, it is necessary and sufficient that the homomorphism iˉ\bar{i} be surjective (Exercise 2 b)).

4) The hypotheses and notations are those of Exerc. 2. Let a,ba, b be two points of the circle C, Δa,Δb\Delta_a, \Delta_b the pointed lines passing through aa and bb (and through 0) respectively, and let θ=(Δa^,Δb^)\theta = (\widehat{\Delta_a}, \widehat{\Delta_b}). For every x∈Ex \in E, distinct from aa and bb, let DxaD_{xa} (resp. DxbD_{xb}) be the affine line passing through aa and xx (resp. bb and xx), and let Dxa′D'_{xa} (resp. Dxb′D'_{xb}) be the direction of DxaD_{xa} (resp. DxbD_{xb}); show that, for x∈Cx \in C (xx distinct from aa and bb), it is necessary and sufficient that the angle φ=(Dxa′^,Dxb′^)\varphi = (\widehat{D'_{xa}}, \widehat{D'_{xb}}) be such that dˉ(φ)=θ\bar{d}(\varphi) = \theta (use Exerc. 3). How is this result modified when x=ax = a or x=bx = b (cf. § 6, Exerc. 25 a))?

5) With the notations of Nos. 1 and 2 and of Exerc. 2, suppose that Φ\Phi is of index 1, in other words that δ\delta is a square γ2\gamma^2 in A; denote by D1,D2D_1, D_2 the isotropic lines of E, containing respectively the vectors e1−1γe2e_1 - \frac{1}{\gamma} e_2 and e1+1γe2e_1 + \frac{1}{\gamma} e_2. a) Show that the group of rotations O+O^+ is isomorphic to the multiplicative group A∗A^* of the field A. b) For every angle θ∈U1\theta \in \mathfrak{U}_1, put ew(θ)=cw(h1(θ))+γsw(h1(0))e_w(\theta) = c_w(h_1(\theta)) + \gamma s_w(h_1(0)). Show that θ→ew(θ)\theta \to e_w(\theta) is an isomorphism of U1\mathfrak{U}_1 onto the group A∗A^*.

c) Let D, D' be any two lines, and let φ=(D^,D′^)\varphi = (\widehat{D}, \widehat{D'}). Show that the cross ratio [D1D2D′D]\begin{bmatrix} D_1 & D_2 \\ D' & D \end{bmatrix} (Chapter II, 2nd ed., App. III, Exerc. 5) is equal to ew(dˉ(φ))e_w(\bar{d}(\varphi)) ("Laguerre formula"). (Observe that D1D_1 and D2D_2 are invariant under every direct similarity, and by using Exerc. 4 c) of Chapter II, 2nd ed., App. III, reduce to the case where D=Ae1D = Ae_1.)

6) Suppose that A is an ordered field. a) Let D1,D2D_1, D_2 be two non-isotropic half-lines with origin 0. Show that there exists a direct similarity uu such that u(D1)=D2u(D_1) = D_2; every other direct similarity having this property is of the form v=suv = su, where s is a homothety with ratio >0> 0.

b) On the set of pairs (D1,D2)(D_1, D_2) of non-isotropic half-lines, the relation “there exists a direct similitude uu such that u(D1)=D1′u(D_1) = D'_1 and u(D2)=D2′u(D_2) = D'_2” is an equivalence relation. The set A\mathfrak{A} of equivalence classes of non-isotropic half-lines, with respect to this relation, is called the set of angles of half-lines (non-isotropic), and the equivalence class of a pair (D1,D2)(D_1, D_2) of such half-lines is called the angle of this pair and denoted by (D1^,D2^)(\widehat{D_1}, \widehat{D_2}); if θ=(D1^,D2^)\theta = (\widehat{D_1}, \widehat{D_2}), one says that θ\theta is the angle of every direct similitude transforming D1D_1 into D2D_2; let h2(θ)h_2(\theta) be the class mod. H+H^+ of these similitudes, so that h2h_2 is a bijection of the set A\mathfrak{A} onto the group S+/H+S^+/H^+; one transports to A\mathfrak{A} by means of h2−1h_2^{-1} the commutative group structure of S+/H+S^+/H^+, denoting additively the group A\mathfrak{A} thus defined. Define a canonical injection jˉ\bar{j} of the group A1\mathfrak{A}_1, of the angles of pointed lines (exerc. 2) into the group A\mathfrak{A}, such that h2∘jˉ∘h2−1h_2 \circ \bar{j} \circ h_2^{-1} is the canonical injection jj of O+O^+ into S+/H+S^+/H^+. For jˉ\bar{j} to be surjective, it is necessary and sufficient that the homomorphism iˉ\bar{i} of A1\mathfrak{A}_1 into A0\mathfrak{A}_0 (exerc. 2 b)) be surjective.

c) Now prove that in A\mathfrak{A} the equation 2θ=02\theta = 0 has 2 solutions if δ<0\delta < 0 and 4 solutions if δ>0\delta > 0. In the first case, the solution ϖ≠0\varpi \neq 0 of this equation is again called the flat angle.

¶ 7) The hypotheses and notations being those of exerc. 6, suppose the homomorphism jˉ\bar{j} bijective; one then defines cos θ\theta and sin θ\theta for every θ∈A\theta \in \mathfrak{A} as in No. 3. Let T be the set of θ∈A\theta \in \mathbf{A} such that sin⁡θ⩾0\sin \theta \geqslant 0.

a) Now prove that for every θ∈T\theta \in T, there exists an angle θ′∈T\theta' \in T, and only one, such that 2θ′=θ2\theta' = \theta; one puts θ′=θ/2\theta' = \theta/2.

b) Let L be the Z\mathbf{Z}-module of formal linear combinations of elements of T with coefficients in Z\mathbf{Z} (Chapter II, § 1, No. 8); denote by ξ+η\xi + \eta and −ξ-\xi the sum and the opposite in L. Let N be the submodule of L generated by the elements of L of the form ξ+η−(ξ+η)\xi + \eta - (\xi + \eta) for all pairs (ξ,η)(\xi, \eta) of elements of T such that ξ+η∈T\xi + \eta \in T (sum taken in the group A\mathfrak{A}). Let f˙\dot{f} be the homomorphism of L into A\mathfrak{A} which extends the canonical injection of T into A\mathfrak{A}, and g˙\dot{g} the endomorphism of L which extends the mapping θ→θ/2\theta \to \theta/2 of T into itself. We have f˙(N)={0}\dot{f}(N) = \{0\} and g˙(N)⊂N\dot{g}(N) \subset N; by passing to quotients, we deduce from f˙\dot{f} a homomorphism ff of M=L/NM = L/N into A\mathfrak{A}, and from g˙\dot{g} an endomorphism gg of MM; we put g(μ)=μ/2g(\mu) = \mu/2 and if gmg^m is the m-th iterate of g, gm(μ)=2−mμg^m(\mu) = 2^{-m}\mu; we have 2m(2−mμ)=μ2^m(2^{-m}\mu) = \mu for every μ∈M\mu \in M.

c) Show that the restriction to T of the canonical mapping ψ\psi of L onto M=L/NM = L/N is injective, which makes it possible to identify T with a subset of M by means of ψ\psi. Show that, if λ1,…,λm\lambda_1, \ldots, \lambda_m are elements ≠0\neq 0 of T, the sum λ1+λ2+⋯+λm\lambda_1 + \lambda_2 + \cdots + \lambda_m cannot be 0 in M (consider the element 2−m(λ1+⋯+λm)2^{-m}(\lambda_1 + \cdots + \lambda_m) and reason by induction on m, observing that these elements belong to T).

d) Let M+M_+ be the set of finite sums (in M) of elements of T; show that M+∩(−M+)={0}M_+ \cap (-M_+) = \{0\} and M=M+∪(−M+)M = M_+ \cup (-M_+), and consequently that M+M_+ is the set of elements ⩾0\geqslant 0 for a totally ordered group structure on M (it will be noted that for every μ∈M+\mu \in M_+, there exists an integer m such that 2−mμ∈T2^{-m}\mu \in T); this totally ordered group is called the group of measures of angles of half-lines. Show that the homomorphism ff of M into A\mathfrak{A} is surjective, and that its kernel is the set of integer multiples of 2π2\pi, where π\pi is the straight angle (Exercise 6 c)). Prove that T is identified with the interval [0,π][0, \pi] in M (establish by induction on m that if μ,λ1,…,λm\mu, \lambda_1, \ldots, \lambda_m belong to T and if one has λ1+⋯+λm⩽μ\lambda_1 + \cdots + \lambda_m \leqslant \mu, then λ1+⋯+λm∈T\lambda_1 + \cdots + \lambda_m \in T). Show that in T (thus identified with an interval of M), the function θ→cos⁡θ\theta \to \cos \theta is strictly decreasing.

e) In order that the totally ordered group M be Archimedean (Chapter VI, § 1, Exercise 31), it is necessary and sufficient that the additive group of the field A be Archimedean. (To see that the condition is necessary, observe that if sin θ\theta is infinitely small with respect to the subfield Q\mathbf{Q} of A (Chapter VI, § 2, Exercise 1), the same is true of sin nθn\theta for every integer n. To see that the condition is sufficient, observe that if 0⩽θ⩽π/40 \leqslant \theta \leqslant \pi/4, one has sin 2θ⩾2sin⁡θ2\theta \geqslant \sqrt{2} \sin \theta).

8) Let E be an oriented plane over an ordered field A. Let D', D'' be two distinct half-lines; let x′x' (resp. x′′x'') be a vector ≠0\neq 0 in D' (resp. D''); the angular sector (open or closed) with origin D' and extremity D'' is said to be salient (resp. re-entrant, straight) if x′∧x′′>0x' \wedge x'' > 0 (resp. x′∧x′′<0,x′∧x′′=0x' \wedge x'' < 0, x' \wedge x'' = 0).

a) In order that there exist an automorphism of the vector space E transforming an open (resp. closed) angular sector Σ1\Sigma_1 into an open (resp. closed) angular sector Σ2\Sigma_2, it is necessary and sufficient that Σ1\Sigma_1 and Σ2\Sigma_2 should be both salient, or both re-entrant, or both flat.

b) Show that the ordered set {D′,D′′}\{D', D''\} is isomorphic to the interval [0,1][0, 1] of A (first consider the case of a salient sector and remark that, in A, any two bounded closed intervals are isomorphic ordered sets).

c) With the notations and hypotheses of Exercise 7, define a canonical bijective mapping of the set T onto a flat angular sector, and show that this mapping is an isomorphism for the order structures.

9) Let A be a Pythagorean ordered field, E a finite-dimensional vector space over A, Q a positive nondegenerate quadratic form on E, for which E admits an orthonormal basis (that is to say, Q(x) is a square in A for every x ∈ E). Show that the commutator group Ω(Q) of the orthogonal group O(Q) is the rotation group O⁺(Q) = SO(Q) (use Exercise 3 e) of § 10 and Exercise 17 a) of § 6).

10) Let A be a maximal ordered field, E a finite-dimensional vector space over A, Q a positive nondegenerate quadratic form on E. For every orthogonal transform u ∈ O(Q), show that there exists a decomposition of E into the direct sum of pairwise orthogonal subspaces P, N, R_i (1 ≤ i ≤ r) having the following properties: 1° u(x) = x in P, u(x) = −x in N ; 2° each of the R_i is of dimension 2, one has u(R_i) = R_i and the restriction of u to R_i is a rotation through an angle θ_i, distinct from 0 and from the flat angle. Moreover, for two decompositions of this nature, the subspaces P and N are the same, as well as the sequence of elements cos θ_i, apart from order (cf. § 7, No. 3, Corollary 2 of Theorem 2). Deduce that every rotation u ∈ O⁺(Q) is a commutator tst⁻¹s⁻¹, where s and t are in O(Q) and s² = 1 (cf. Exercise 3 d)).

11) Let A be a maximal ordered field, L the field of quaternions over A (relative to the pair (−1, −1)), E the subspace (of dimension 3) of L consisting of pure quaternions (§ 9, Exercise 15 a)) ; every quaternion is therefore written in one and only one way s = α . 1 + v, where α ∈ A and v ∈ E ; one has α² − v² = ρ . 1, where ρ ∈ A and ρ ≥ 0 ; put \|v\| = \sqrt{\rho}.

a) Let φ(s) be the rotation x → sx s⁻¹ in E, for the positive nondegenerate quadratic form x → \|x\|^2 on E (§ 9, No. 5, Theorem 4 and Exercise 15). Show that if v ≠ 0, the vectors of the line D ⊂ E containing v are invariant under φ(s) ; the restriction of φ(s) to the orthogonal plane P = D⁰ is a rotation through an angle θ such that (for a suitable orientation of P) one has tg \frac{\theta}{2} = \|v\|/α. (If (1, i, j, k) is the canonical basis of L over A, reduce to the case where v = βi, β ∈ A, and then calculate sjs⁻¹).

b) Show that every quaternion of norm 1 can be written tst⁻¹s⁻¹, where s ∈ L, t ∈ E (cf. Exercise 10), and that, if a, b are two pure quaternions of norm 1, there exists a quaternion s such that b = sas⁻¹.

c) In order that two quaternions s = α + v, t = β + w, where α, β are in A, v, w in E, should commute, it is necessary and sufficient that v = λw, λ ∈ A ; in order that st = −ts, it is necessary and sufficient that α = β = 0 and that the vectors v and w in E should be orthogonal (cf. § 3, Exercise 10).

12) Let A be a maximal ordered field, L a Euclidean space of dimension n over A, whose metric form Φ is positive nondegenerate ; let d(x, y) denote the distance \sqrt{\Phi(x - y, x - y)} of two points of L (§ 7, No. 1, Remark). For every point c ∈ L and every element ρ > 0 of A, the set of x ∈ L such that d(x, c) = ρ is called the sphere with center c and radius ρ ; the spheres are therefore nondegenerate affine quadrics in L, admitting a center (§ 6, Exercise 25).

a) Show that at every point x of a sphere S with center c, the tangent hyperplane to S at x (§ 6, Exercise 25) is perpendicular (§ 6, Exercise 22) to the line through c and x.

b) Let S be a sphere with center c and radius ρ, a a point of L, D a line through a and meeting S in two distinct points x₁, x₂ (resp. tangent to S at a point x). Show that one has

Φ(x1−a,x2−a)=(d(a,c))2−ρ2(resp. (d(x,a))2=(d(a,c))2−ρ2). \Phi(x_1 - a, x_2 - a) = (d(a, c))^2 - \rho^2 \quad (\text{resp. } (d(x, a))^2 = (d(a, c))^2 - \rho^2).

The element (d(a,c))2−ρ2(d(a, c))^2 - \rho^2 of A is called the power of a with respect to S.

c) Let S₁, S₂ be two spheres not having the same center ; show that the set of points of L whose powers with respect to S₁ and S₂ are equal is a hyperplane perpendicular to the line through the centers of the two spheres, and containing the intersection S₁ ∩ S₂ ; one says that this hyperplane is the radical hyperplane of S₁ and S₂.

d) Let S₁, S₂ be two spheres with respective centers c₁, c₂, and respective radii ρ₁, ρ₂. Show that the following properties are equivalent :

α) The intersection S₁ ∩ S₂ is not empty and, for every point of this intersection, the tangent hyperplanes to S₁ and S₂ at this point are perpendicular.

β1\beta_1 The power of c₁ with respect to S₂ is ρ12\rho_1^2.

β2\beta_2 The power of c₂ with respect to S₁ is ρ22\rho_2^2.

γ1\gamma_1 The radical hyperplane of S₁ and S₂ is the polar hyperplane (§ 6, Exercise 25) of c₁ with respect to S₂.

γ2\gamma_2 The radical hyperplane of S₁ and S₂ is the polar hyperplane of c₂ with respect to S₁.

When these properties are satisfied, one says that the spheres S₁, S₂ are orthogonal.

e) Let S₁, S₂ be two orthogonal spheres, c1,c2c_1, c_2 their centers. Show that if ϖ1,ϖ2\varpi_1, \varpi_2 are the powers of a point x with respect to S₁, S₂ respectively, one has ϖ1+ϖ2=2Φ(x−c1,x−c2)\varpi_1 + \varpi_2 = 2\Phi(x - c_1, x - c_2). Converse.

13) The hypotheses and notations are the same as in Exercise 12. Given a point c ∈ L and an element α≠0\alpha \neq 0 of A, the involutive permutation u of the set L−{c}L - \{ c \} such that, for every x∈L−{c}x \in L - \{ c \}, u(x)u(x) belongs to the line passing through c and x and satisfies the relation Φ(x−c,u(x)−c)=α\Phi(x - c, u(x) - c) = \alpha is called the inversion with pole c and power α\alpha. By abuse of language, one says that u is an inversion in L.

a) If u, v are two inversions with the same pole c and with powers α,β\alpha, \beta, uv−1uv^{-1} is the restriction to L−{c}L - \{ c \} of the homothety (Chapter II, 2nd ed., App. II, Exercise 6) with center c and ratio αβ−1\alpha \beta^{-1}.

b) Let S be a sphere (Exercise 12) containing c. Show that the image of S−{c}S - \{ c \} under an inversion with pole c is a hyperplane perpendicular to the line joining c to the center of S (by abuse of language, this hyperplane is said to be the image of S under the inversion considered). Converse.

c) Let S be a sphere not containing c. Show that, if ϖ\varpi is the power of c with respect to S (Exercise 12 b)), the image of S under an inversion with pole c and power α\alpha is the image of S under a homothety with center c and ratio α/ϖ\alpha / \varpi. If n=2n = 2 and if, for every x∈Sx \in S, T (resp. T’) denotes the tangent to S (resp. u(S)u(S)) at the point x (resp. u(x)u(x)), D the line passing through c, x and u(x)u(x), show that one has (D,T^)=(T′,D^)(\widehat{D, T}) = (\widehat{T', D}).

d) Let S1,S2S_1, S_2 be two orthogonal spheres (Exercise 12 d)), S1′,S2′S'_1, S'_2 their images under an inversion with pole cc. If cc does not belong to S1S_1 or to S2S_2, show that S1′S'_1 and S2′S'_2 are orthogonal spheres. If c∈S1c \in S_1 and c∉S2c \notin S_2, S1′S'_1 is a hyperplane containing the center of S2′S'_2. If c∈S1∩S2c \in S_1 \cap S_2, S1′S'_1 and S2′S'_2 are perpendicular hyperplanes (§ 6, Exercise 22). Converses.

e) Let uu be an inversion with pole cc and power α=ρ2>0\alpha = \rho^2 > 0 and C the sphere with center cc and radius ρ\rho. If x1,x2x_1, x_2 are two distinct points situated on a line passing through cc, and distinct from cc, the following properties are equivalent: α)\alpha ) x1x_1 and x2x_2 are transformed into one another by u;β)u ; \beta ) x1x_1 and x2x_2 are conjugate with respect to CC (§ 6, Exercise 25); γ)\gamma ) every sphere containing x1x_1 and x2x_2 is orthogonal to CC. One also says that uu is the inversion of sphere CC.

¶ 14) The hypotheses and notations being the same as in Exercise 12, choose an origin 0 in L. Let E1E_1 be the vector space direct sum of L and of a space Af1Af_1 of dimension 1; denote by Q1Q_1 the quadratic form on E1E_1 such that for x∈Lx \in L and η∈A\eta \in A, one has

Q1(x+ηf1)=Q(x)+η2, Q_1(x + \eta f_1) = Q(x) + \eta^2,

a form which is positive and non-degenerate; denote by CC the sphere with center 0 and radius 1 in E1E_1 (for Q1Q_1).

In the Euclidean space E1E_1, let ss be the inversion with pole −f1-f_1 and power 2 (Exercise 13); its restriction s0s_0 to L transforms L into C−{−f1}C - \{ -f_1 \}; s0s_0 (resp. s0−1s_0^{-1}) is called, by an abuse of language, the stereographic projection of L onto C (resp. of C onto L) from the point of view −f1-f_1. For every inversion uu in L, with pole cc, s0us0−1s_0 us_0^{-1} is an involutive permutation of the complement in C of the set {s0(c),−f1}\{ s_0(c), -f_1 \}; this is extended to an involutive permutation u′u' of C by putting u′(s0(c))=−f1, u′(−f1)=s0(c)u'(s_0(c)) = -f_1,\ u'(-f_1) = s_0(c), and one says that u′u' is an inversion in C. Analogously, for every symmetry ν\nu in L with respect to a hyperplane, s0νs0−1s_0 \nu s_0^{-1} is an involutive permutation of the complement in C of the set {−f1}\{ -f_1 \}; this is extended to an involutive permutation ν′\nu' of C by putting ν′(−f1)=−f1\nu'(-f_1) = -f_1 and one says that ν′\nu' is a symmetry in C. The group of permutations of C generated by the inversions and symmetries is called the conformal group of C (or of L, by an abuse of language).

a) Now prove that the conformal group of C is generated by the symmetries ν′\nu' and the inversions u′u' corresponding to inversions uu in L of power >0> 0. (Use Exercise 13 a) and remark that in L every translation, as well as the homothety x→−xx \to -x, is a product of symmetries with respect to hyperplanes).

b) Let uu be an inversion in L of power >0> 0; now prove that the corresponding inversion u′u' in C is the restriction to C of a well-determined transform u1′u'_1 which is either an inversion of power >0> 0 in E1E_1, whose sphere (Exercise 13 e)) is orthogonal to C, or a symmetry with respect to a hyperplane of E1E_1 passing through 0 (consider in E1E_1 the inversion u1u_1 with the same pole and the same power as uu). Formulate the corresponding proposition for the symmetry ν′\nu' in C corresponding to a symmetry ν\nu in L with respect to a hyperplane.

c) In the vector space E2=A×E1E_2 = A \times E_1, consider the quadratic form Q2Q_2 such that, for ζ∈A,y∈E1\zeta \in A, y \in E_1, one has

Q2((ζ,y))=ζ2−Q1(y), Q_2((\zeta, y)) = \zeta^2 - Q_1(y),
a form which is nondegenerate and of signature (1,n+1)(1, n + 1). Identify E1E_1 with its canonical image in the projective space P(E2)\mathbf{P}(E_2) (Chapter II, 2nd ed., App. III, No. 4). Now prove (with the notations of bb) that u′u' is also the restriction to CC of a projective linear mapping uˉ′′\bar{u}'' arising by passing to the quotients from a transform u′′u'' of the orthogonal group O(Q2)O(Q_2), which is a symmetry with respect to a nonisotropic hyperplane in E2E_2. State the corresponding proposition for φ′\varphi'. Deduce that the conformal group of LL is isomorphic to the quotient of the group O(Q2)O(Q_2) by its center (use proposition 5 and Exercise 17 c) of § 6). Conclude from this that every transform of the conformal group is a product of at most n+2n + 2 transforms which are inversions or symmetries in LL (cf. § 6, Exercise 15 e)).

dd ) Let Σ\Sigma be the set whose elements are the spheres and the hyperplanes in the affine space LL. Deduce from bb that there exists a bijection of Σ\Sigma onto the complement, in P(E2)\mathbf{P}(E_2), of the set of x∈E1x \in E_1 such that Q1(x)⩽1Q_1(x) \leqslant 1, such that to two orthogonal spheres there correspond two points conjugate with respect to CC.

15) Generalize the definitions and results of Exercises 12 to 14 to the case where AA is a Pythagorean field and where there exists an orthonormal basis for Φ\Phi.

16) Let AA be a commutative field, VV a vector space over AA of odd dimension 2r+12r + 1, FF the product space A×VA \times V, Ψ′\Psi' a nondegenerate alternating form on FF; in the projective space P(F)\mathbf{P}(F), of dimension 2r+12r + 1, one says that the set C0C_0 of lines which are the canonical images of the totally isotropic planes of FF (for Ψ′\Psi') is the linear (projective) complex associated with Ψ′\Psi'.

Suppose in what follows that AA is maximal ordered; let Φ\Phi be a positive non-degenerate symmetric form on VV. Let DD be the right orthogonal to VV (for Ψ′\Psi') in FF, which is contained in VV, and let HH be the hyperplane orthogonal to DD (for Φ\Phi) in VV; in FF, HH is a non-isotropic subspace for Ψ′\Psi', whose orthogonal for Ψ′\Psi' is therefore a plane supplementary to HH and containing DD. In the affine space E={1}×V⊂FE = \{1\} \times V \subset F, the set CC of the intersections with EE of the totally isotropic planes of FF (for Ψ′\Psi') not contained in VV is again called the (affine) linear complex associated with Ψ′\Psi'; the right Δ=P∩E\Delta = P \cap E is called the axis of the linear complex CC (for the Euclidean space structure defined on EE by the metric form Φ\Phi).

a) Now prove that, in EE, every translation equal to a direction vector of Δ\Delta (Chapter II, 2nd ed., App. II, No. 3) leaves CC invariant (cf. § 4, Exercise 6).

b) Let (ei)0≤i≤2r(e_i)_{0 \leq i \leq 2r} be an orthonormal basis of VV for Φ\Phi, such that e0∈De_0 \in D and that Ψ′(e2i−1,e2i)=ρi>0\Psi'(e_{2i-1}, e_{2i}) = \rho_i > 0 for 1≤i≤r1 \leq i \leq r, Ψ′(ej,ek)=0\Psi'(e_j, e_k) = 0 for pairs of indices which are not of the form (e2i−1,e2i)(e_{2i-1}, e_{2i}) or (e2i,e2i−1)(e_{2i}, e_{2i-1}) (§ 7, No. 3, Prop. 6). Take in the affine space E an origin a∈Δa \in \Delta, and put Ψ(a,e0)=ρ0\Psi(a, e_0) = \rho_0. Let xx be a vector belonging to the plane generated by e2i−1e_{2i-1} and e2ie_{2i}, and let yy be the vector of this same plane such that Φ(x,y)=0\Phi(x, y) = 0, Φ(y,y)=1\Phi(y, y) = 1 and that x∧y=λe2i−1∧e2ix \wedge y = \lambda e_{2i-1} \wedge e_{2i} with λ>0\lambda > 0. Let EiE_i be the 3-dimensional affine linear variety generated by the points a,a+e0,a+e2i−1,a+e2ia, a + e_0, a + e_{2i-1}, a + e_{2i} in E, and let RxR_x be the intersection of EiE_i and the affine hyperplane (in E) generated by the lines of C containing the point a+xa + x. Show that the direction of the lines orthogonal (for Φ\Phi) to the plane RxR_x in EiE_i is a line LxL_x in the plane Ae0+AyAe_0 + Ay, such that if θ=(D^,Lx^)\theta = (\widehat{D}, \widehat{L_x}), one has

tg⁡θ=ρiρ0Φ(x,x) \operatorname{tg} \theta = \frac{\rho_i}{\rho_0} \sqrt{\Phi(x, x)}

when the plane Ae0+AyAe_0 + Ay is oriented in such a way that e0∧ye_0 \wedge y is positive.

¶ 17) a) Let A be a commutative field, J:ξ→ξ‾J : \xi \to \overline{\xi} an involutive automorphism of A, E a 2-dimensional vector space over A, Φ\Phi a non-degenerate (non-alternating) hermitian sesquilinear form on E, (e1,e2)(e_1, e_2) an orthogonal basis of E for Φ\Phi (§ 6, No. 1, Th. 1), such that

Φ(ξ1e1+ξ2e2,η1e1+η2e2)=αξ1η1‾+βξ2η2‾ \Phi(\xi_1 e_1 + \xi_2 e_2, \eta_1 e_1 + \eta_2 e_2) = \alpha \xi_1 \overline{\eta_1} + \beta \xi_2 \overline{\eta_2}

(α(\alpha and β\beta belonging to the field K of invariants of J); put γ=β/α\gamma = \beta / \alpha. Identify the point ξ1e1+ξ2e2∈E\xi_1 e_1 + \xi_2 e_2 \in E with the element ξ1+ξ2ρ\xi_1 + \xi_2 \rho of the ring B defined by the conditions ρ2=−γ\rho^2 = -\gamma, ρξ=ξ‾ρ\rho \xi = \overline{\xi} \rho for ξ∈A\xi \in A (§ 3, Exercise 4 a)). For every x=ξ1+ξ2ρ∈Bx = \xi_1 + \xi_2 \rho \in B, put x~=ξ1‾−ξ2ρ\tilde{x} = \overline{\xi_1} - \xi_2 \rho and N(x)=xx~=x~xN(x) = x \tilde{x} = \tilde{x} x, so that x→x~x \to \tilde{x} is an involutive antiautomorphism of the algebra B (over K) and that one has Φ(x,x)=αN(x)\Phi(x, x) = \alpha N(x). Show that every similarity for Φ\Phi whose determinant is equal to the multiplier (also called a direct similarity) can be written in one and only one way x→xyx \to xy, where yy is a non-isotropic vector of E, and that its multiplier is N(y)N(y).

b) Suppose first that J is the identity, hence K=AK = A. If A is of characteristic ≠2\neq 2, thus recover the results of No. 1. Develop the corresponding theory when A is of characteristic 2 (cf. § 4, Exercise 14; one will distinguish two cases, according as γ\gamma is or is not a square in A).

c) Suppose J≠1J \neq 1, so that A is a separable quadratic extension of K. Then Φ\Phi necessarily satisfies condition (T) (§ 4, No. 2 and Exercise 1); if Φ\Phi is of index 0, B is a reflexive field with center K (Chapter VIII, § 11, Exercise 4), and if Φ\Phi is of index 1, B is isomorphic to M2(K)\mathbf{M}_2(K).

d) Suppose J≠1J \neq 1 and A of characteristic ≠2\neq 2; then A=K(θ)A = K(\theta) with θ2=−δ∈K\theta^2 = -\delta \in K. If S is the group of direct similitudes for Φ\Phi, H the group of homotheties in E, with ratio ≠0\neq 0 and belonging to K (a group isomorphic to K∗K^*), now prove that the group S/H is isomorphic to the group of rotations O+(Q)O^+(Q), where Q is a nondegenerate quadratic form on a vector space F of dimension 3 over K, such that there exists an orthogonal basis (f1,f2,f3)(f_1, f_2, f_3) of F for which one has

Q(ζ1f1+ζ2f2+ζ3f3)=γζ12+δζ22+γδζ32 Q(\zeta_1 f_1 + \zeta_2 f_2 + \zeta_3 f_3) = \gamma \zeta_1^2 + \delta \zeta_2^2 + \gamma \delta \zeta_3^2

(cf. § 9, Exercise 15).

¶ 18) a) Let AA be a commutative field, ξ→ξˉ\xi \to \bar{\xi} an involutory automorphism of AA, EE a vector space of even dimension 2m2m over AA, Φ\Phi a nondegenerate Hermitian form of index 0 on EE, satisfying condition (T), Δ\Delta the discriminant of Φ\Phi with respect to a basis of EE. Let M(Φ)M(\Phi) be the group of multipliers of similitudes for Φ\Phi (§4§ 4, Exercise 8). Now prove that M(Φ)M(\Phi) is a subgroup of the multiplicative group of elements of AA of the form ααˉ−(−1)mββˉΔ\alpha \bar{\alpha} - (-1)^m \beta \bar{\beta} \Delta. (Argue by induction on mm, using Exercise 17, together with the following two remarks: 1° if uu is a similitude with multiplier μ\mu, xx a vector of EE, y=u(x)y = u(x) and z=u(y)z = u(y), there exists a unitary transform vv such that v(y)=yv(y) = y and v(z)=μxv(z) = \mu x; 2° if α,β,λ\alpha, \beta, \lambda are three elements ≠0\neq 0 of AA such that there exist a,b,c,da, b, c, d in AA satisfying the conditions λ=aaˉ+αccˉ\lambda = a \bar{a} + \alpha c \bar{c}, λ=bbˉ+βddˉ\lambda = b \bar{b} + \beta d \bar{d}, then there exist s,ts, t in AA satisfying the condition λ=ssˉ−αβttˉ\lambda = s \bar{s} - \alpha \beta t \bar{t}.

b) Let KK be a maximal ordered field, K1=K((t1))K_1 = K((t_1)) the field of formal power series in an indeterminate t1t_1, with coefficients in KK (Chapter IV, §5§ 5, No. 7), A=K1((t2))A = K_1((t_2)) the field of formal power series in a second indeterminate t2t_2, with coefficients in K1K_1. Let EE be a vector space of dimension 6 over AA, QQ a nondegenerate quadratic form on EE, such that there exists an orthogonal basis (ei)(e_i) for which one has

Q(∑i=16ξiei)=ξ12+ξ22+ξ32+ξ42+t1ξ52+t2ξ62. Q\left( \sum_{i=1}^{6} \xi_i e_i \right) = \xi_1^2 + \xi_2^2 + \xi_3^2 + \xi_4^2 + t_1 \xi_5^2 + t_2 \xi_6^2.

Show that there exists no similarity for QQ with multiplier t1t2t_1 t_2.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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