Bourbaki

Example

Tag 0DRE, permanent. Cite it as [Bourbaki, Tag 0DRE].

Algebra, chapter X, § 2. Complexes de A-modules

If CC has zero differential, one has Z(C)=CZ(C) = C, B(C)=0B(C) = 0 and H(C)H(C) identifies canonically with CC.

There are exact sequences, called canonical:

(In_n)

0→Zn(C)→Cn→δnBn−1(C)→0 0 \to Z_n(C) \to C_n \xrightarrow{\delta_n} B_{n-1}(C) \to 0
(IIn_n)
0→Bn(C)→Zn(C)→Hn(C)→0 0 \to B_n(C) \to Z_n(C) \to H_n(C) \to 0
(IIIn_n)
0→Bn(C)→Cn→Cn/Bn(C)→0 0 \to B_n(C) \to C_n \to C_n/B_n(C) \to 0
(IVn_n)
0→Hn(C)→Cn/Bn(C)→δ‾nBn−1(C)→0 0 \to H_n(C) \to C_n/B_n(C) \xrightarrow{\overline{\delta}_n} B_{n-1}(C) \to 0

where δn\delta_n and δ‾n\overline{\delta}_n are deduced from dnd_n. By combining (IVn_n) and (IIn−1_{n-1}), one obtains the exact sequence

(Vn_n)

0→Hn(C)→Cn/Bn(C)→Zn−1(C)→Hn−1(C)→0, 0 \to H_n(C) \to C_n/B_n(C) \to Z_{n-1}(C) \to H_{n-1}(C) \to 0 ,

which is also written, changing nn into −n-n

(Vn^n)

0→Hn(C)→Cn/Bn(C)→Zn+1(C)→Hn+1(C)→0. 0 \to H^n(C) \to C^n/B^n(C) \to Z^{n+1}(C) \to H^{n+1}(C) \to 0 .

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

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Translated with machine help, not yet reviewed by a person.