Bourbaki

Theorem 1

Tag 0DRJ, permanent. Cite it as [Bourbaki, Tag 0DRJ].

Algebra, chapter X, § 2. Complexes de A-modules

The unlimited sequence of homomorphisms of AA-*modules*

⋯⟶Hn+1(C′′)→∂n+1(u,v)Hn(C′)→Hn(u)Hn(C)→Hn(v)Hn(C′′) \cdots \longrightarrow H_{n+1}(C'') \xrightarrow{\partial_{n+1}(u,v)} H_n(C') \xrightarrow{H_n(u)} H_n(C) \xrightarrow{H_n(v)} H_n(C'')
→∂n(u,v)Hn−1(C′)→Hn−1(u)Hn−1(C)→Hn−1(v)Hn−1(C′′)→∂n−1(u,v)Hn−2(C′)⟶⋯ \xrightarrow{\partial_n(u,v)} H_{n-1}(C') \xrightarrow{H_{n-1}(u)} H_{n-1}(C) \xrightarrow{H_{n-1}(v)} H_{n-1}(C'') \xrightarrow{\partial_{n-1}(u,v)} H_{n-2}(C') \longrightarrow \cdots

is exact.

This sequence is called the exact homology sequence associated with the exact sequence (u,v)(u,v); it is sometimes written in the form of an exact triangle of AA-*modules*

H(C)↗H(u)↘H(v)H(C′)←∂(u,v)H(C′′). \begin{array}{ccc} &&H(C)\\ &\nearrow^{H(u)}&\searrow^{H(v)}\\ H(C')&\xleftarrow{\partial(u,v)}&H(C'') . \end{array}

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

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Translated with machine help, not yet reviewed by a person.