Let C be a complex. Consider the canonical exact sequence
(I)
0⟶Z(C)jCδB(C)(−1)⟶0,
and let i:B(C)→Z(C) be the canonical injection. Then the linking homomorphism ∂(j,δ):H(B(C))(−1)→H(Z(C))(−1) identifies with H(i)(−1), as one verifies at once. Since H(δ)=0, the homology exact sequence associated to (I) decomposes into the short exact sequences
(II_n)
0⟶Bn(C)iZn(C)H(j)Hn(C)⟶0.
\* Mappings :
1) Singular homology
Let A be a ring. For any topological space X, we define the singular complex C(X,A) of X with coefficients in A as follows:
In R(N), denote by (en) the canonical basis; we call the n-canonical simplex the convex hull Δn of {e0,...,en}. For i∈{0,...,n}, we define the affine mapping ιi:Δn−1→Δn by ιi(ek)=ek for k<i and ιi(ek)=ek+1 for k≥i. We denote Cn(X,A) the a-module A(Σn(X)), where Σn(X) is the set of continuous mappings from Δn into X; for n<0, we set Cn=0. For i∈{0,...,n}, we define the linear mapping ∂n,i:Cn(X,A)→Cn−1(X,A) by ∂n,i(es)=es∘ιi for s∈Σn(X), and we set dn=Σ(−1)i∂n,i. We verify that
...Cn(X,A)dnCn−1(X,A)→...
is a complex. Its homology is called the singular homology of X with coefficients in A and is denoted H(X,A) or simply H(X).
If Y is a subspace of X, we denote C(X,Y,A) the quotient complex C(X,A)/C(Y,A), and H(X,Y,A) its homology. It follows from Theorem 1 that there is an exact sequence:
Let X be a separated topological space. A finite cell decomposition of X is given by an increasing sequence (Xn)n∈Z of closed subspaces of X satisfying the following conditions: (i) Xn=∅ for n<0; (ii) there exists an N such that XN=X (hence Xn=X for n>N); (iii) for every n, the space Xn−Xn−1 has only a finite number of connected components, called the n-dimensional cells; (iv) for every n, and for every connected component C of Xn−Xn−1, there exists a homeomorphism from the open n-dimensional euclidean ball B^n (TG, VI, p. 10) onto C that extends to a continuous mapping of the closed ball into X.
One can show that these conditions imply that Hn(Xn,Xn−1,A) is a free a-module Γn of rank equal to the number of n-dimensional cells, and that Hi(Xn,Xn−1,A)=0 for i=n. We have C(Xn,Xn−1,A)=C(Xn,Xn−2,A)/C(Xn−1,Xn−2,A), hence an exact sequence
shows by induction on p that Hn(Xp)=0 for p<n, that Hn(Xn)=Ker(dn:Γn→Γn−1) and that Hn(Xp)=Hn(Γ) for p>n. In particular Hn(X) is identified with Hn(Γ).
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.