Bourbaki

Example

Tag 0DS8, permanent. Cite it as [Bourbaki, Tag 0DS8].

Algebra, chapter X, § 2. Complexes de A-modules

Let u:M→Nu : M \to N be a homomorphism of A-modules; then the only non-zero homogeneous components of Cyl (u)\mathrm{Cyl}\,(u) and Con (u)\mathrm{Con}\,(u) are

Cyl1 (u)=M,Cyl0 (u)=M⊕N, \mathrm{Cyl}_1\,(u) = M , \qquad \mathrm{Cyl}_0\,(u) = M \oplus N ,
Con1 (u)=M,Con0 (u)=N, \mathrm{Con}_1\,(u) = M , \qquad \mathrm{Con}_0\,(u) = N ,
and we have D‾(m)=(m,−u(m))\overline{D}(m) = (m, -u(m)), D(m)=−u(m)D(m) = -u(m) for m∈Mm \in M; consequently,
H1(Con (u))=Ker (u),H0(Con (u))=Coker (u). H_1(\mathrm{Con}\,(u)) = \mathrm{Ker}\,(u) , \quad H_0(\mathrm{Con}\,(u)) = \mathrm{Coker}\,(u) .

Let XX and YY be two topological spaces and ff a continuous mapping from XX into YY. The cylinder of ff is called the quotient space Cyl (f)\mathrm{Cyl}\,(f) of the topological sum of [0,1]×X[0, 1] \times X and YY by the equivalence relation identifying the point (1,x)(1, x) of [0,1]×X[0, 1] \times X with the point f(x)f(x) of YY for every x∈Xx \in X. The cone of ff is called the quotient space Con (f)\mathrm{Con}\,(f) of the topological sum of a space reduced to a point ss and Cyl (f)\mathrm{Cyl}\,(f) by the equivalence relation identifying ss with the image of (0,x)(0, x) for every x∈Xx \in X: we still denote by ss the image of ss in Con (f)\mathrm{Con}\,(f).

Suppose that XX and YY are endowed with cellular decompositions (Xn)(X_n) and (Yn)(Y_n) (cf. No. 3), and suppose that f(Xn)⊂Ynf(X_n) \subset Y_n for every nn. We obtain a cellular decomposition (Sn)(S_n) of Cyl (f)\mathrm{Cyl}\,(f) (resp. of Con (f)\mathrm{Con}\,(f)) by taking for SnS_n the image of ({0}×Xn)∪([0,1]×Xn−1)∪Yn(\{0\} \times X_n) \cup ([0, 1] \times X_{n-1}) \cup Y_n

(resp. of {s}∪([0,1]×Xn−1)∪Yn,if n⩾0). (\text{resp. of } \{s\} \cup ([0, 1] \times X_{n-1}) \cup Y_n , \quad \text{if } n \geqslant 0) .
Let Γ(X),Γ(Y),Γ(Cyl (f)),Γ(Con (f))\Gamma(X), \Gamma(Y), \Gamma(\mathrm{Cyl}\,(f)), \Gamma(\mathrm{Con}\,(f)) denote the complexes associated with these cellular decompositions.

The complex Γ(s)\Gamma(s) associated with the space {s}\{ s \} endowed with its unique cellular decomposition is reduced to the module A\mathbf{A} and is identified with a subcomplex of Γ(Con (f))\Gamma(\mathrm{Con}\,(f)); let Γ(Con (f), s)\Gamma(\mathrm{Con}\,(f),\,s) denote the quotient complex. The mapping ff defines a morphism of complexes Γ(f):Γ(X)→Γ(Y)\Gamma(f) : \Gamma(X) \to \Gamma(Y), and one can show that the complexes Γ(Cyl (f))\Gamma(\mathrm{Cyl}\,(f)) and Γ(Con (f), s)\Gamma(\mathrm{Con}\,(f),\,s) are identified respectively with Cyl (Γ(f))\mathrm{Cyl}\,(\Gamma(f)) and Con (Γ(f))\mathrm{Con}\,(\Gamma(f)).

Par ailleurs, et sans hypothèses sur XX et YY, on associe à ff un morphisme de complexes f∗:C(X, A)→C(Y, A)f_* : C(X,\,\mathbf{A}) \to C(Y,\,\mathbf{A}). On peut construire des homotopismes injectifs de Cyl (f∗)\mathrm{Cyl}\,(f_*) dans C(Cyl (f), A)C(\mathrm{Cyl}\,(f),\,\mathbf{A}) et de Con (f∗)\mathrm{Con}\,(f_*) dans C(Con (f), {s}, A)C(\mathrm{Con}\,(f),\,\{s\},\,\mathbf{A}). Soient f~:X→Cyl (f)\tilde{f} : X \to \mathrm{Cyl}\,(f) l'application qui à xx associe l'image de (0, x)(0,\,x), α:Y→Cyl (f)\alpha : Y \to \mathrm{Cyl}\,(f) l'application canonique et β:Cyl (f)→Y\beta : \mathrm{Cyl}\,(f) \to Y l'application qui associe yy à son image dans Cyl (f)\mathrm{Cyl}\,(f) pour y∈Yy \in Y et f(x)f(x) à l'image de (t, x)(t,\,x) dans Cyl (f)\mathrm{Cyl}\,(f) pour t∈[0, 1]t \in [0,\,1] et x∈Xx \in X. L'application f~\tilde{f} est un homéomorphisme de XX sur un fermé de Cyl (f)\mathrm{Cyl}\,(f), on a β∘α=IdY\beta \circ \alpha = \mathrm{Id}_Y, et α∘β\alpha \circ \beta est topologiquement homotope à l'identité de Cyl (f)\mathrm{Cyl}\,(f). Ces propriétés sont à rapprocher de la proposition 7 ci-dessous. \*

Considérons maintenant les applications A\mathbf{A}-linéaires graduées de degré 0

u~:C′→Cyl (u) ,u~(x′)=(x′, 0, 0) ,α:C→Cyl (u) ,α(x)=(0, 0, x) ,β:Cyl (u)→C ,β(x′, y′, x)=u(x′)+x ,π:C→Con (u) ,π(x)=(0, x) ,π~:Cyl (u)→Con (u) ,π~(x′, y′, x)=(y′, x) ,δ:Con (u)→C′(−1) ,δ(y′, x)=y′ . \begin{align*} \tilde{u} : C' &\to \mathrm{Cyl}\,(u)\,, & \tilde{u}(x') &= (x',\,0,\,0)\,, \\ \alpha : C &\to \mathrm{Cyl}\,(u)\,, & \alpha(x) &= (0,\,0,\,x)\,, \\ \beta : \mathrm{Cyl}\,(u) &\to C\,, & \beta(x',\,y',\,x) &= u(x') + x\,, \\ \pi : C &\to \mathrm{Con}\,(u)\,, & \pi(x) &= (0,\,x)\,, \\ \tilde{\pi} : \mathrm{Cyl}\,(u) &\to \mathrm{Con}\,(u)\,, & \tilde{\pi}(x',\,y',\,x) &= (y',\,x)\,, \\ \delta : \mathrm{Con}\,(u) &\to C'(-1)\,, & \delta(y',\,x) &= y'\,. \end{align*}

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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