Let C be a bounded complex of type C. a) If C is stable, H(C) is of type C. b) If H(C) is of type C, it is analogously the case for B(C) and Z(C), and one has χ(H(C))=χ(C).
a) If C is stable, for every n the module Zn(C) is of type C as kernel of dn:Cn→Cn−1, and Hn(C) is of type C as cokernel of Cn+1→Zn. On the other hand, Hn(C)=0 as soon as Cn=0.
b) Suppose H(C) of type C. The canonical exact sequences:
0→Zn(C)→Cn→Bn−1(C)→0
0→Bn(C)→Zn(C)→Hn(C)→0
show by induction on n starting from the right bound of C that Zn(C) and Bn(C) are of type C for all n. One then has
χ(C)=χ(Z(C))+χ(B(C)(−1))=χ(Z(C))−χ(B(C))=χ(H(C)).
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.