*Let C,C~,C′,C~′ be four A-complexes, u:C~→C,v:C~→C,u′:C′→C~′ and v′:C′→C~′ four morphisms of complexes.
a) If u and u′ are homotopic to v and v′ respectively, then the two morphisms HomgrA(u,u′) and HomgrA(v,v′) from HomgrA(C,C′) to HomgrA(C~,C~′) are homotopic.
b) If u and u′ are homotopisms, HomgrA(u,u′) is a homotopism.
c) If C or C′ is homotopic to zero, HomgrA(C,C′) is homotopic to zero.*
Let us denote by the same letter d the differentials of the complexes C, C1, C′, C1′, and by D the differentials of HomgrA(C,C′) and HomgrA(C1,C1′). If u (resp. u′) is homotopic to v (resp. v′), there exists a graded homomorphism of degree 1,
w:C1→C(resp. w′:C′→C1′)
such that
u−v=dw+wd(resp. u′−v′=dw′+w′d)(2)
Let W:HomgrA(C,C′)→HomgrA(C1,C1′) be the graded homomorphism of degree 1 such that, for f∈HomgrA(C,C′)n, n∈Z, one has
W(f)=w′fu+(−1)nv′fw.(3)
We then have
(DW+WD)(f)=D[w′fu+(−1)nv′fw]+W[df−(−1)nfd]
=dw′fu−(−1)n+1w′fud+(−1)ndv′fw+v′fwd
+w′dfu+(−1)n+1v′dfw−(−1)nw′fdu+v′fdw
=(dw′+w′d)fu+v′f(wd+dw)
=(u′−v′)fu+v′f(u−v)=u′fu−v′fv;
This is written as DW+WD=HomgrA(u,u′)−HomgrA(v,v′), whence a).
Let us prove b). If u and u′ are homotopy equivalences, let α:C→C and α′:C′→C′ be morphisms of complexes such that u∘α, α∘u, u′∘α′, α′∘u′ are homotopic respectively to IdC, IdC, IdC′, IdC′. Then Homgr(u,u′)∘Homgr(α,α′), which is equal to Homgr(α∘u,u′∘α′), is homotopic by a) to
HomgrA(IdC,IdC′)=IdHomgrA(C,C′);
analogously Homgr(α,α′)∘Homgr(u,u′) is homotopic to IdHomgr(C,C′), whence b).
Finally c) follows from b) (applied to the case where C or C′ is zero).
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.