If C is split and H(C) projective (resp. if C′ is split and Hn(C′) injective for each n), then the canonical homomorphism
λ(C,C′):H(HomgrA(C,C′))→HomgrA(H(C),H(C′))
is bijective.
Suppose for example C′ split and H(C′) injective for each n, the case where C is split and H(C) projective being proved in an analogous manner. By X, p. 35, def. 6, there exists a homotopy equivalence u′:C′→H(C′) ; by Proposition 3, HomgrA(1,u′) is a homotopy equivalence from HomgrA(C,C′) onto HomgrA(C,H(C′)) ; since
and that HomgrA(1,H(u′)) and H(HomgrA(1,u′)) are bijective, it is enough for us to prove that λ(C,H(C′)) is bijective, which brings us back to the case where C′ is injective and has zero differential.
The canonical exact sequences (X, p. 28)
(III)
0→B(C)iCδC/B(C)→0
(IV)
0→H(C)jC/B(C)δB(C)→0
give exact sequences (X, p. 83, Proposition 2, a))
Since dC=i∘δ∘p, the differential D of HomgrA(C,C′) is given by Dn=(−1)n+1Pn∘Δn∘ln; we then have
Z(HomgrA(C,C′))=Ker(P∘Δ∘I)=KerI=ImP,
B(HomgrA(C,C′))=Im(P∘Δ∘I)=P(ImΔ)=P(KerJ);
whence an isomorphism φ:H(HomgrA(C,C′))→HomgrA(H(C),C′) such that, if a∈HomgrA(C/B(C),C′), the image of the class of P(a) under φ is J(a); we immediately verify that φ coincides with the canonical homomorphism λ.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.