Bourbaki

Proposition 7

Tag 0DX0, permanent. Cite it as [Bourbaki, Tag 0DX0].

Algebra, chapter X, § 5. Modules d’extensions

Let II and JJ be two sets, (Mα)α∈I(M_\alpha)_{\alpha\in I} and (Nβ)β∈J(N_\beta)_{\beta\in J} two families of AA-modules; the homomorphism

Ext⁡A(⨁α∈IMα,∏β∈JNβ)⟶∏β∈J, α∈IExt⁡A(Mα,Nβ) \operatorname{Ext}_A\left(\bigoplus_{\alpha\in I}M_\alpha,\prod_{\beta\in J}N_\beta\right) \longrightarrow \prod_{\substack{\beta\in J,\ \alpha\in I}} \operatorname{Ext}_A(M_\alpha,N_\beta)
induced by the canonical homomorphisms Mα→⨁α∈IMαM_\alpha \to \bigoplus_{\alpha\in I} M_\alpha and ∏β∈JNβ→Nβ\prod_{\beta\in J} N_\beta \to N_\beta is bijective.

It suffices to prove that for every AA-module MM (resp. NN), the homomorphisms

Ext⁡(M,∏βNβ)→∏βExt⁡(M,Nβ) \operatorname{Ext}(M, \prod_\beta N_\beta) \to \prod_\beta \operatorname{Ext}(M,N_\beta)
(resp. Ext⁡(⨁Mα,N)→∏αExt⁡(Mα,N)\operatorname{Ext}(\bigoplus M_\alpha,N)\to\prod_\alpha\operatorname{Ext}(M_\alpha,N)) are bijective. This follows from what has already been shown, from Proposition 1 of X, p. 28, and the canonical isomorphisms Homgr⁡A(L(M),∏Nβ)→∏Homgr⁡A(L(M),Nβ)\operatorname{Homgr}_A(L(M), \prod N_\beta) \to \prod \operatorname{Homgr}_A(L(M),N_\beta) and Homgr⁡A(⨁Mα,I(N))→∏Homgr⁡A(Mα,I(N))\operatorname{Homgr}_A(\bigoplus M_\alpha, I(N)) \to \prod \operatorname{Homgr}_A(M_\alpha, I(N)).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Nothing.

Translated with machine help, not yet reviewed by a person.