Proposition 2
Tag 0E0V, permanent. Cite it as [Bourbaki, Tag 0E0V].
Algebra, chapter X, § 8. Dimension homologique
Assume A left noetherian. Let M be a finitely generated a-module and n an integer . The following conditions are equivalent:
(i) .
(i bis) M possesses a projective resolution P of length such that is a finitely generated a-module for each .
(ii) for every finitely generated a-module N and every integer .
(iii) for every finitely generated a-module N.
(iv) for every right a-module P and every .
(v) for every finitely generated right ideal of A.
(i bis) (i) : this is trivial.
(i) (ii) : this follows from Lemma 1.
(ii) (iii) : this is trivial.
(iii) (i) : by (iii) and X, p. 107, prop. 5, we have for every a-module N, whence (i) by prop. 1.
(i) (iv) : this follows from Lemma 1.
(iv) (v) : this is trivial.
(v) (i bis) : let (L,d) be a free resolution of M such that is finitely generated for all (X, p. 53, prop. 6). Set ; then K is finitely generated as a submodule of and we have an exact sequence
By (v) and X, p. 131, cor. 3, we have for every finitely generated right ideal of A. By th. 2 of X, p. 74, the a-module K is flat; since it is finitely generated, hence of finite presentation (X, p. 10, prop. 5), it is projective (X, p. 13, cor.), so (1) is a projective resolution of M.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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