Bourbaki

Proposition 3

Tag 0E0X, permanent. Cite it as [Bourbaki, Tag 0E0X].

Algebra, chapter X, § 8. Dimension homologique

a) If dpA(M)⩽n\mathrm{dp}_A(M) \leqslant n, the canonical homomorphism (3) is injective. b) If dpA(M)⩽n\mathrm{dp}_A(M) \leqslant n, if AA is left noetherian and if MM is of finite type, the canonical homomorphism (3) is bijective.

We argue by induction on nn. If n=0n = 0, MM is projective, the homomorphism (3) reduces to the canonical homomorphism P⊗AM→Hom⁡A(M∗,P)P \otimes_A M \to \operatorname{Hom}_A(M^*, P) of II, p. 77, and the proposition follows from loc. cit., corollary. If n>0n > 0, let

(4)

0→N→L→M→0 0 \to N \to L \to M \to 0

be an exact sequence of AA-modules where LL is free (and of finite type in case b); then dpA(N)⩽n−1\mathrm{dp}_A(N) \leqslant n - 1 (X, p. 135, cor. 2, c)) and NN is of finite type in case b.

Let θ∈Ext⁡A1(M,N)\theta \in \operatorname{Ext}_A^1(M, N) be the class associated with the exact sequence (4) (X, p. 117, déf. 1). Denote

un:Ext⁡An−1(N,A)→Ext⁡An(M,A)vn:Tor⁡nA(P,M)→Tor⁡n−1A(P,N) u_n : \operatorname{Ext}_A^{n-1}(N, A) \to \operatorname{Ext}_A^n(M, A) \qquad v_n : \operatorname{Tor}_n^A(P, M) \to \operatorname{Tor}_{n-1}^A(P, N)
the mappings defined by un(α)=α∘θu_n(\alpha) = \alpha \circ \theta and vn(β)=θ∘βv_n(\beta) = \theta \circ \beta. We have
(α∘θ)∘β=α∘(θ∘β) (\alpha \circ \theta) \circ \beta = \alpha \circ (\theta \circ \beta)

for all α∈Ext⁡An−1(N,A)\alpha\in\operatorname{Ext}_A^{n-1}(N,A), β∈Tor⁡nA(P,M)\beta\in\operatorname{Tor}_n^A(P,M) (X, p. 129, prop. 6), so that the diagram

Tor⁡nA(P,M)⟶Hom⁡A(Ext⁡An(M,A),P)↓vn↓Hom⁡(un,1)Tor⁡n−1A(P,N)⟶Hom⁡A(Ext⁡An−1(N,A),P),(5) \begin{array}{ccc} \operatorname{Tor}_n^A(P,M)&\longrightarrow&\operatorname{Hom}_A(\operatorname{Ext}_A^n(M,A),P)\\ \downarrow v_n&&\downarrow\operatorname{Hom}(u_n,1)\\ \operatorname{Tor}_{n-1}^A(P,N)&\longrightarrow&\operatorname{Hom}_A(\operatorname{Ext}_A^{n-1}(N,A),P), \end{array} \tag{5}

where the horizontal arrows are the canonical homomorphisms, is commutative.

If n=1n=1, we thus have a commutative diagram:

00↓↓Tor⁡1A(P,M)⟶Hom⁡A(Ext⁡A1(M,A),P)↓v1↓Hom⁡(u1,1)P⊗AN⟶Hom⁡A(N∗,P)↓↓P⊗AL⟶Hom⁡A(L∗,P) \begin{array}{ccccc} 0&&&&0\\ \downarrow&&&&\downarrow\\ \operatorname{Tor}_1^A(P,M)&\longrightarrow&\operatorname{Hom}_A(\operatorname{Ext}_A^1(M,A),P)\\ \downarrow v_1&&&&\downarrow\operatorname{Hom}(u_1,1)\\ P\otimes_A N&\longrightarrow&\operatorname{Hom}_A(N^*,P)\\ \downarrow&&&&\downarrow\\ P\otimes_A L&\longrightarrow&\operatorname{Hom}_A(L^*,P) \end{array}

where the columns are exact; this yields the result in this case. If n≥2n\geq 2, the mappings unu_n and vnv_n are bijective (X, p. 128, cor. 4 and p. 131, cor. 3). By the induction hypothesis, the canonical homomorphism

Tor⁡n−1A(P,N)⟶Hom⁡A(Ext⁡An−1(N,A),P) \operatorname{Tor}_{n-1}^A(P,N)\longrightarrow\operatorname{Hom}_A(\operatorname{Ext}_A^{n-1}(N,A),P)

is injective (resp. bijective); the diagram (5) shows that the same holds for the canonical homomorphism Tor⁡nA(P,M)⟶Hom⁡A(Ext⁡An(M,A),P)\operatorname{Tor}_n^A(P,M)\longrightarrow\operatorname{Hom}_A(\operatorname{Ext}_A^n(M,A),P), which completes the proof.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

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Cites

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