Bourbaki

Remark

Tag 0E13, permanent. Cite it as [Bourbaki, Tag 0E13].

Algebra, chapter X, § 8. Dimension homologique

By the equivalence of (i) and (iii), we have dh(A)=dh(A∘)\mathrm{dh}(A) = \mathrm{dh}(A^\circ) if AA is left and right noetherian. This equality is not valid in general (X, p. 204, Exercise 20).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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