Bourbaki

Proposition 7

Tag 0E16, permanent. Cite it as [Bourbaki, Tag 0E16].

Algebra, chapter X, § 8. Dimension homologique

The following conditions are equivalent : (i) dh(A)≤1\mathrm{dh}(A) \leq 1, (ii) every submodule of a projective module is projective, (ii') every ideal of AA is projective, (iii) every quotient of an injective a-module is injective, (iv) for every projective complex CC, there exists a homomorphism φ:C→H(C)\varphi : C \to H(C) such that H(φ)=1H(C)H(\varphi) = 1_{H(C)}, (v) for every injective complex CC, there exists a homomorphism ψ:H(C)→C\psi : H(C) \to C such that H(ψ)=1H(C)H(\psi) = 1_{H(C)}.

(i) ⇔ (ii) ⇔ (iii) : this follows from Prop. 4 of X, p. 138. (ii) ⇒ (iv) : let CC be a projective complex. If (ii) is satisfied, the submodule B(C)B(C) of CC is projective, hence (iv) by X, p. 35, Remark b). (iii) ⇒ (v) : let CC be an injective complex. If (iii) is satisfied, the quotient Bn(C)B_n(C) of Cn+1C_{n+1} is injective for all nn, hence (v) by X, p. 35, Remark a). (iv) ⇒ (ii) : let PP be a projective a-module, MM a submodule of PP, and i:M→Pi : M \to P the canonical injection. Let p:L→Mp : L \to M be a surjective homomorphism from a free module LL onto MM. Consider the projective complex CC such that C1=LC_1 = L, C0=PC_0 = P, Ci=0C_i = 0 for i≠0,1i \ne 0, 1, and d1=i∘pd_1 = i \circ p. If (iv) is satisfied, let φ:C→H(C)\varphi : C \to H(C) be a homomorphism such that H(φ)=1H(C)H(\varphi) = 1_{H(C)}. Since H1(C)=Ker pH_1(C) = \mathrm{Ker}\ p, φ1\varphi_1 is a projector of LL onto Ker p\mathrm{Ker}\ p, so the exact sequence

0→Ker p→L→pM→0 0 \to \mathrm{Ker}\ p \to L \xrightarrow{p} M \to 0

is split and MM is isomorphic to a direct factor of LL, hence projective.

(v)⇒(iii)(v)\Rightarrow(iii) : let II be an injective module, MM a quotient of II, and π:I→M\pi : I \to M the canonical projection. Let i:M→Ji : M \to J be an injective homomorphism of MM into an injective module JJ. Consider the injective complex CC such that C0=IC^0 = I, C1=JC^1 = J, Ci=0C^i = 0 for i≠0,1i \ne 0, 1, and d0=i∘πd^0 = i \circ \pi. If (v) is satisfied, let ψ:H(C)→C\psi : H(C) \to C be a homomorphism such that H(ψ)=1H(C)H(\psi) = 1_{H(C)}. Since

H1(C)=Coker⁡i, H^1(C) = \operatorname{Coker}i,

ψ1\psi^1 is a section of the canonical projection J→Coker⁡iJ \to \operatorname{Coker}i, and MM is a direct factor in JJ, hence injective.

(ii)⇒(ii′)(ii)\Rightarrow(ii') : this is trivial.

(ii′)⇒(ii)(ii')\Rightarrow(ii) : this follows from VII, § 3, Corollary 1 to Theorem 1.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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