Library / Algebra / Chapter X / § 8
Lemma 5
Tag 0E1G, permanent. Cite it as [Bourbaki, Tag 0E1G].
Algebra, chapter X, § 8. Dimension homologique
Let M M M be a graded A A A -module bounded below, and let
s : A ⊗ A 0 M / J 0 M → M
s : A \otimes_{A_0} M/J_0 M \to M
s : A ⊗ A 0 M / J 0 M → M be a graded
A A A -homomorphism such that
1 ⊗ A s : A 0 ⊗ A ( A ⊗ A 0 M / J 0 M ) → A 0 ⊗ A M 1 \otimes_A s : A_0 \otimes_A (A \otimes_{A_0} M/J_0 M) \to A_0 \otimes_A M 1 ⊗ A s : A 0 ⊗ A ( A ⊗ A 0 M / J 0 M ) → A 0 ⊗ A M is the canonical isomorphism. Then
s s s is surjective. If
T o r 1 A ( A 0 , M ) = 0 \mathrm{Tor}_1^A(A_0, M) = 0 Tor 1 A ( A 0 , M ) = 0 ,
s s s is bijective.
We have an exact sequence
0 → K e r s → A ⊗ A 0 M J 0 M → M → C o k e r s → 0
0 \to \mathrm{Ker}\ s \to A \otimes_{A_0} M J_0 M \to M \to \mathrm{Coker}\ s \to 0
0 → Ker s → A ⊗ A 0 M J 0 M → M → Coker s → 0 and the graded
A A A -modules
K e r s \mathrm{Ker}\ s Ker s and
C o k e r s \mathrm{Coker}\ s Coker s are bounded below. From the exact sequence
A 0 ⊗ A ( A ⊗ A 0 M / J 0 M ) → 1 ⊗ s A 0 ⊗ A M → A 0 ⊗ A C o k e r s → 0 A_0 \otimes_A (A \otimes_{A_0} M/J_0 M) \xrightarrow{1 \otimes s} A_0 \otimes_A M \to A_0 \otimes_A \mathrm{Coker}\ s \to 0 A 0 ⊗ A ( A ⊗ A 0 M / J 0 M ) 1 ⊗ s A 0 ⊗ A M → A 0 ⊗ A Coker s → 0 , we deduce that
A 0 ⊗ A C o k e r s = 0 A_0 \otimes_A \mathrm{Coker}\ s = 0 A 0 ⊗ A Coker s = 0 , hence
s s s is surjective (Lemma 4). We then have an exact sequence
T o r 1 A ( A 0 , M ) → A 0 ⊗ A K e r s → A 0 ⊗ A ( A ⊗ A 0 M / J 0 M ) → 1 ⊗ s A 0 ⊗ A M .
\mathrm{Tor}_1^A(A_0, M) \to A_0 \otimes_A \mathrm{Ker}\ s \to A_0 \otimes_A (A \otimes_{A_0} M/J_0 M) \xrightarrow{1 \otimes s} A_0 \otimes_A M .
Tor 1 A ( A 0 , M ) → A 0 ⊗ A Ker s → A 0 ⊗ A ( A ⊗ A 0 M / J 0 M ) 1 ⊗ s A 0 ⊗ A M . If
T o r 1 A ( A 0 , M ) = 0 \mathrm{Tor}_1^A(A_0, M) = 0 Tor 1 A ( A 0 , M ) = 0 , then
A 0 ⊗ A K e r s = 0 A_0 \otimes_A \mathrm{Ker}\ s = 0 A 0 ⊗ A Ker s = 0 and
s s s is injective (Lemma 4).
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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