Exercise 15, § 3
Commutative Algebra, II
Bourbaki marks this one as harder than the rest.
Let A be a (commutative) ring, M an A-module.
a) In order that a submodule of M be pure (Chapter I, § 2, Exercise 24), it is necessary and sufficient that, for every maximal ideal of A, be a pure sub--module of (use Theorem 1 of No. 3).
b) Suppose that A is a local ring with maximal ideal , and M a free a-module of finite type. In order that a submodule of finite type of M be pure, it is necessary and sufficient that it be a direct factor of M. (Using Corollary 1 of Proposition 5 of No. 2, reduce to proving that, if can only be a pure submodule of M if .)
Solution
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