Bourbaki

Exercise 16, § 3

Commutative Algebra, II

Let (Aλ,fμλ)(A_\lambda, f_{\mu\lambda}) be a filtered inductive system of local rings, such that the fμλf_{\mu\lambda} are local homomorphisms; let mλm_\lambda be the maximal ideal of AλA_\lambda, and let Kλ=Aλ/mλK_\lambda = A_\lambda / m_\lambda. Then A=lim⁡←AλA = \lim \leftarrow A_\lambda is a local ring whose m=lim⁡←mλm = \lim \leftarrow m_\lambda is the maximal ideal and K=lim⁡→KλK = \lim \rightarrow K_\lambda the residue field. Moreover, if one has mμ=Aμmλm_\mu = A_\mu m_\lambda for λ<μ\lambda < \mu, one has m=Amλm = Am_\lambda for every λ\lambda.

Solution

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.