Bourbaki

Exercise 24, § 2

Commutative Algebra, III

On a commutative ring AA, denote by Cm(A)\mathscr{C}_m(A) the linear topology for which a fundamental system of neighbourhoods of 00 is formed by the products (equal to the intersections) of a finite number of powers of maximal ideals (cf. No. 13, Prop. 17); denote by Cu(A)\mathscr{C}_u(A) the linear topology for which a fundamental system of neighbourhoods of 00 is formed by all the ideals ≠{0}\neq \{0\} of AA.

a) Now prove that Cc(A)\mathscr{C}_c(A) (Exercise 23) is less fine than Cm(A)\mathscr{C}_m(A) (observe that the radical of an artinian ring is nilpotent); give an example where Cc(A)≠Cm(A)\mathscr{C}_c(A) \neq \mathscr{C}_m(A) (cf. Exercise 22 c)). If AA is a non-discrete valuation ring of rank 1 (Chapter VI), one has Cc(A)=Cm(A)\mathscr{C}_c(A) = \mathscr{C}_m(A) and Cu(A)≠Cm(A)\mathscr{C}_u(A) \neq \mathscr{C}_m(A).

b) The topology Cm(A)\mathscr{C}_m(A) is the least fine of the linear topologies on AA for which the maximal ideals of AA are closed and every power of an open ideal of AA is an open ideal (note that for a linear topology on AA for which a maximal ideal mm is closed, mm is necessarily open).

c) If AA is a noetherian ring, one has Cm(A)=Ce(A)\mathscr{C}_m(A) = \mathscr{C}_e(A) (observe that if mm is a maximal ideal of AA, A/mkA/m^k is an artinian ring for every integer k≥1k \geq 1, by noting that mn/mn+1m^n/m^{n+1} is necessarily a module of finite length over (A/m)(A/m)). Give an example of a noetherian local ring AA for which Cm(A)≠Cu(A)\mathscr{C}_m(A) \neq \mathscr{C}_u(A) (consider a local ring of a polynomial ring over a field).

Solution

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