Bourbaki

Exercise 29, § 2

Commutative Algebra, III

Let AA be a commutative ring, m\mathfrak{m} an ideal of AA such that ⋂n≥0mn=0\bigcap_{n \geq 0} \mathfrak{m}^n = 0, cc an element of AA which is not a divisor of 0. Now prove that the transporters qn=mn:Acq_n = \mathfrak{m}^n : Ac are open for the m\mathfrak{m}-adic topology and have an intersection reduced to 0. If AA is strictly linearly compact for the m\mathfrak{m}-adic topology (Exercise 22 b)), (qn)(q_n) is a fundamental system of neighborhoods of 0 in AA for this topology.

Solution

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Machine translation of the English, by gpt-5-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.