Exercise 31, § 2
Commutative Algebra, IV
Bourbaki marks this one as harder than the rest.
a) Let be a noetherian ring, a maximal ideal of , a prime ideal contained in ; now prove that if the separated completion of for the -adic topology is integral, the filter basis of the symbolic powers of tends to for the -adic topology in . (Reduce to the case where is local; let be a prime ideal of whose trace on is , and for every , let such that ; now prove that one has . Use Exercise 29 e), as well as Chapter III, § 2, No. 7, Proposition 8.)
b) Let be a noetherian ring, an ideal of , a minimal prime ideal in , two maximal ideals of containing ; denote by the separated completions of for the -adic, -adic, -adic topologies respectively. Let be an element of whose canonical image in is zero. Now prove that if is integral, the canonical image of in is zero also. (Take as the limit of a sequence of elements of such that for , and ; deduce that belongs to the closure of for the -adic topology; using Exercise 8, conclude that for every ; complete using a.)
c) Let be a Zariski ring, a defining ideal of ; suppose that is connected and that for every maximal ideal of , the separated completion of for the -adic topology is integral. Now prove that the completion of for the -adic topology is integral. (Now prove that for every maximal ideal of , the canonical homomorphism is injective. For this, one may suppose that is the intersection of a finite number of prime ideals, minimal in , namely ; now prove that the assumption on implies for each the existence of a maximal ideal containing . Using , now prove that if the canonical image of in is zero and if, for example, , then the canonical image of in each of the is zero, then conclude that the canonical image of in is zero for every maximal ideal of .)
Solution
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