Bourbaki

Exercise 17, § 1

Commutative Algebra, IX

Let A be the ring Q[X]\mathbf{Q}[X]. Let Ω=(Ωn)n∈N\Omega = (\Omega_n)_{n \in \mathbf{N}} be the element of A such that ΦA(Ω)=(X,X,...,X,...)\Phi_A(\Omega) = (X, X, ..., X, ...). For every element aa of Zp\mathbf{Z}_p, put

Ω(a)=(Ωn(a))n∈N. \Omega(a) = (\Omega_n(a))_{n \in \mathbf{N}}.

a) For every a∈Zpa \in \mathbf{Z}_p, and every integer n∈Nn \in \mathbf{N}, one has Ωn(a)∈Zp\Omega_n(a) \in \mathbf{Z}_p.

b) For every a∈Za \in \mathbf{Z} and every integer n∈Nn \in \mathbf{N}, one has Ωn(a)∈Z\Omega_n(a) \in \mathbf{Z}, and, if a∈Na \in \mathbf{N}, Ω(a)\Omega(a) is the element of W(Z)W(\mathbf{Z}) equal to the sum of aa terms each equal to the unit element of W(Z)W(\mathbf{Z}).

c) The mapping a↦Ω(a)a \mapsto \Omega(a) defines a homomorphism of Zp\mathbf{Z}_p into W(Zp)W(\mathbf{Z}_p) which, when Zp\mathbf{Z}_p is identified with W(Fp)W(F_p) (§ 1, No. 7, Example 3), coincides with the homomorphism sFps_{F_p} defined in Exercise 15.

Solution

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Machine translation of the English, by gpt-5.4. Not checked by a person.