Bourbaki

Exercise 4, § 1

Commutative Algebra, IX, p. 42

Let AA be a ring, a=(an)n∈Na = (a_n)_{n \in \mathbf{N}} an element of W(A)W(A), a(p)a^{(p)} the element (anp)n∈N(a_n^p)_{n \in \mathbf{N}} of W(A)W(A). Put

b=(bn)n∈N=p.a−Va(p). b = (b_n)_{n \in \mathbf{N}} = p.a - Va^{(p)}.

Prove that one has bn−pan∈pp−1Ab_n - pa_n \in p^{p-1}A for every n∈Nn \in \mathbf{N}. (Reduce to the case where A=Z[(Xn)n∈N]A = \mathbf{Z}[(X_n)_{n \in \mathbf{N}}] and a=(Xn)n∈Na = (X_n)_{n \in \mathbf{N}} and use Prop. 1 of § 1, No. 1.)

Solution

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Machine translation of the English, by gpt-5.4. Not checked by a person.