Bourbaki

Exercise 54, § 1

Commutative Algebra, IX, p. 64

Let CC be a ring and AA a CC-algebra (not necessarily commutative). We denote by RepC(A)\mathrm{Rep}_C(A) the additive set of classes of AA-modules which are projective CC-modules of finite type, and by RC(A)R_C(A) the grothendieck group K(RepC(A))K(\mathrm{Rep}_C(A)) (cf. A, VIII, § 10, No. 6). a) Let α:A′→A\alpha : A' \to A be a homomorphism of CC-algebras. If EE is an AA-module of type RepC(A)\mathrm{Rep}_C(A), then the module α∗E\alpha_*E obtained by restriction of the ring of scalars AA to A′A' (A, II, p. 30) is an A′A'-module of type RepC(A′)\mathrm{Rep}_C(A'), and [E]↦[α∗E][E] \mapsto [\alpha_*E] defines a homomorphism α∗:RC(A)→RC(A′)\alpha_* : R_C(A) \to R_C(A').

EXERCISES

If α1:A1→A′\alpha_1 : A_1 \to A' is a homomorphism of C-algebras, one has (α∘α1)∗=α1∗∘α∗(\alpha \circ \alpha_1)_* = \alpha_{1*} \circ \alpha_*.

b) Put K0(C)=RC(C)K_0(C) = R_C(C). The structural homomorphism ε:C→A\varepsilon : C \to A defines a homomorphism ε∗:RC(A)→K0(C)\varepsilon_* : R_C(A) \to K_0(C). If there exists a homomorphism γ:A→C\gamma : A \to C of C-algebras, then γ∗:K0(C)→RC(A)\gamma_* : K_0(C) \to R_C(A) is a right inverse of ε∗\varepsilon_*.

c) Let γ:C→C′\gamma : C \to C' be a homomorphism of rings. If E is an A-module of type RepC(A)\mathrm{Rep}_C(A), then γ∗E=C′⊗CE\gamma^*E = C' \otimes_C E is an AC′A_{C'}-module of type RepC′(AC′)\mathrm{Rep}_{C'}(A_{C'}), where AC′=C′⊗CAA_{C'} = C' \otimes_C A, and [E]↦[γ∗E][E] \mapsto [\gamma^*E] defines a homomorphism γ∗:RC(A)→RC′(AC′)\gamma^* : R_C(A) \to R_{C'}(A_{C'}). If γ1′:C′→C1\gamma'_1 : C' \to C_1 is another homomorphism of rings, one has (γ1∘γ)∗=γ1∗∘γ∗(\gamma_1 \circ \gamma)^* = \gamma_1^* \circ \gamma^*.

d) Let E→fF→gGE \xrightarrow{f} F \xrightarrow{g} G be homomorphisms of A-modules, and put h=g∘fh = g \circ f. Construct an exact sequence of A-modules

(∗)0→Ker(f)→Ker(h)→Ker(g)→Coker(f)→Coker(h)→Coker(g)→0. (*) \quad 0 \to \mathrm{Ker}(f) \to \mathrm{Ker}(h) \to \mathrm{Ker}(g) \to \mathrm{Coker}(f) \to \mathrm{Coker}(h) \to \mathrm{Coker}(g) \to 0 .

Deduce from this that if ff and gg are injective, and if Coker(f)\mathrm{Coker}(f) and Coker(g)\mathrm{Coker}(g) are of type RepC(A)\mathrm{Rep}_C(A), then Coker(h)\mathrm{Coker}(h) is of type RepC(A)\mathrm{Rep}_C(A), and one has

[Coker(h)]=[Coker(f)]+[Coker(g)] [\mathrm{Coker}(h)] = [\mathrm{Coker}(f)] + [\mathrm{Coker}(g)]

in RC(A)R_C(A).

Solution

No solution has been written yet.

Machine translation of the English, by gpt-5.4. Not checked by a person.