Bourbaki

Exercise 55, § 1

Commutative Algebra, IX, p. 65

Let C be a ring. Let G be a monoid and let C(G)C^{(G)} be its algebra over C. Instead of RepC(C(G))\mathrm{Rep}_C(C^{(G)}) and RC(C(G))R_C(C^{(G)}), we shall write RepC(G)\mathrm{Rep}_C(G) and RC(G)R_C(G). If α:G′→G\alpha : G' \to G is a homomorphism of monoids, we shall also denote by α\alpha the homomorphism of C-algebras C(G′)→C(G)C^{(G')} \to C^{(G)} which it defines, and by α∗:RC(G)→RC(G′)\alpha_* : R_C(G) \to R_C(G') the corresponding homomorphism.

By A, VIII, § 10, No. 5, there exists on RC(G)R_C(G) a structure of (commutative) ring such that

[E].[F]=[E⊗CF] [E].[F] = [E \otimes_C F]

if E and F are modules of type RepC(G)\mathrm{Rep}_C(G). The identity element for this multiplication is the class of the module C1C_1, equal to C with trivial action of G.

a) The ring RC(G)R_C(G) admits a unique structure of pre-λ\lambda-ring such that

λ[E]=∑n≥0[Λn(E)]Tn \lambda[E] = \sum_{n \geq 0} [\Lambda^n(E)] T^n

for every module E of type RepC(G)\mathrm{Rep}_C(G). (Observe first of all that Λn(E)\Lambda^n(E) is again a module of type RepC(G)\mathrm{Rep}_C(G). Next, if F is a submodule such that F and E/F are of type RepC(G)\mathrm{Rep}_C(G), now prove that

[Λn(E)]=∑p=0n[Λp(F)⊗CΛn−p(E/F)] [\Lambda^n(E)] = \sum_{p=0}^n [\Lambda^p(F) \otimes_C \Lambda^{n-p}(E/F)]

in RC(G)R_C(G). For this purpose let us denote by LpL_p the image of Λp(F)⊗CΛn−p(E)\Lambda^p(F) \otimes_C \Lambda^{n-p}(E), under multiplication, in Λn(E)\Lambda^n(E). We have Λn(E)=L0⊃L1⊃...⊃Ln=Λn(F)⊃Ln+1=0\Lambda^n(E) = L_0 \supset L_1 \supset ... \supset L_n = \Lambda^n(F) \supset L_{n+1} = 0, and there exists a canonical isomorphism of C(G)C^{(G)}-modules from Lp/Lp+1L_p/L_{p+1} onto Λp(F)⊗Λn−p(E/F)\Lambda^p(F) \otimes \Lambda^{n-p}(E/F).

b) For every homomorphism α:G′→G\alpha : G' \to G of monoids, the map α∗:RC(G)→RC(G′)\alpha_* : R_C(G) \to R_C(G') is a λ\lambda-morphism. In particular K0(C)K_0(C) is a pre-λ\lambda-ring and ε∗:RC(G)→K0(C)\varepsilon_* : R_C(G) \to K_0(C) is a λ\lambda-morphism. The homomorphism G→{1}G \to \{1\} furnishes a right inverse for it.

c) Let G be a monoid and R a set. A function f:G→Rf : G \to R will be said to be central if f(st)=f(ts)f(st) = f(ts) for every s,t∈Gs, t \in G. Let us denote by FC(G, R) the set of these functions. If R is a λ\lambda-ring, FC(G, R) is canonically endowed with a structure of λ\lambda-ring such that

(f+f′)(s)=f(s)+f′(s) (f + f')(s) = f(s) + f'(s)
(f.f′)(s)=f(s).f′(s) (f.f')(s) = f(s).f'(s)
(λnf)(s)=λn(f(s)) (\lambda_n f)(s) = \lambda_n(f(s))

for every f,f′f, f' in FC(G, R) and s in G. This applies in particular when R=Λ(C)R = \Lambda(C).

d) Let E be a module of type Rep_C(G). For every s ∈ G, let us denote by s_E the homothety of ratio s in E, and put

χ‾E(s)=det⁡E[T](1+sET)∈Λ(C) \overline{\chi}_E(s) = \det_{E[T]}(1 + s_E T) \in \Lambda(C)

(cf. p. 62, Exercise 49). Now prove that

χ‾:[E]↦χ‾E \overline{\chi} : [E] \mapsto \overline{\chi}_E

defines a λ\lambda-morphism

χ‾:RC(G)→FC(G,Λ(C)). \overline{\chi} : R_C(G) \to FC(G, \Lambda(C)) .

e) If C is a field, then χ‾\overline{\chi} is injective (A, VIII, § 10, No. 6, Proposition 10). Deduce in this case that RC(G)R_C(G) is a λ\lambda-ring.

Solution

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Machine translation of the English, by gpt-5.4. Not checked by a person.