Bourbaki

Exercise 56, § 1

Commutative Algebra, IX, p. 66

Let GG be the free monoid generated by an element T, so that C(G)C^{(G)} is identified with C[T]C[T]. Let C0C_0 denote the module C[T]/TC[T]C[T]/TC[T]. Then [C0][C_0] is an idempotent element of RC(C[T])R_C(C[T]). The kernel of the canonical λ\lambda-morphism RC(C[T])→K0(C)R_C(C[T]) \to K_0(C) is the ideal generated by 1−[C0]1 - [C_0]. Put

R~C(C[T])=RC(C[T])/[C0].RC(C[T]). \tilde{R}_C(C[T]) = R_C(C[T])/[C_0].R_C(C[T]) .

a) Now prove that [C0].RC(C[T])[C_0].R_C(C[T]) is a λ\lambda-ideal, hence that R~C(C[T])\tilde{R}_C(C[T]) admits a quotient structure of pre-λ\lambda-ring. b) For every module E of type RepC(C[T])Rep_C(C[T]), let TET_E denote the homothety of ratio T in E. We have

χ‾E(T)=det⁡E[T](1+TET)∈Λ(C) \overline{\chi}_E(T) = \det_{E[T]}(1 + T_E T) \in \Lambda(C)

and

χE(T)=det⁡E[T](T−TE) \chi_E(T) = \det_{E[T]}(T - T_E)

is the characteristic polynomial of TET_E (cf. exerc. 49, p. 62). Now prove that [E]↦χ‾E(T)[E] \mapsto \overline{\chi}_E(T) defines a λ\lambda-morphism RC(C[T])→Λ(C)R_C(C[T]) \to \Lambda(C) whose kernel contains [C0][C_0]. By passing to the quotient, one obtains a λ\lambda-morphism

χ‾:R~C(C[T])→Λ(C). \overline{\chi} : \tilde{R}_C(C[T]) \to \Lambda(C) .

c) Let Λrat(C)\Lambda_{rat}(C) denote the subgroup of Λ(C)\Lambda(C) generated by the elements of Λ(C)\Lambda(C) which are polynomials in T. Now prove that the image of χ‾\overline{\chi} is Λrat(C)\Lambda_{rat}(C). Conclude that Λrat(C)\Lambda_{rat}(C) is a sub-λ\lambda-ring of Λ(C)\Lambda(C).

d) For every r∈Zr \in \mathbf{Z}, define σr:C[T,T−1]→C[T,T−1]\sigma_r : C[T, T^{-1}] \to C[T, T^{-1}] by (σrf)(T)=Trf((−T)−1)(\sigma_r f)(T) = T^r f(( - T)^{-1}). We have (σr(σsf))(T)=(−1)sTr−sf(T)(\sigma_r(\sigma_s f))(T) = (-1)^s T^{r-s} f(T), in particular σr(σrf)=(−1)rf\sigma_r(\sigma_r f) = (-1)^r f, and (σrf).(σsg)=σr+s(f.g)(\sigma_r f).(\sigma_s g) = \sigma_{r+s}(f.g), whatever r,sr, s in Z\mathbf{Z} and f,gf, g in C[T,T−1]C[T, T^{-1}]. If ff is a polynomial in T of degree ≤r\leq r (r≥0r \geq 0), then σrf\sigma_r f is one also. If moreover f∈Λ(C)f \in \Lambda(C) (i.e. f(0)=1f(0) = 1), then σrf\sigma_r f is monic of degree rr. If E is a C[T]C[T]-module which is a free CC-module of rank rr, then σr(χ‾E(T))=χE(T)\sigma_r(\overline{\chi}_E(T)) = \chi_E(T).

e) If f∈Λ(C)f \in \Lambda(C) is a polynomial in T of degree ≤r\leq r, put Er,f=C[T]/σrf.C[T]E_{r,f} = C[T]/\sigma_r f.C[T]; it is a free CC-module of rank rr. If f=1f = 1 we have Er,1=C[T]/TrC[T]E_{r,1} = C[T]/T^r C[T]. If g∈Λ(C)g \in \Lambda(C) is a polynomial in T of degree ≤s\leq s, we have an exact sequence of C[T]C[T]-modules

(∗)0→Es,g→Er+s,fg→Er,f→0 (*) \quad 0 \to E_{s,g} \to E_{r+s, fg} \to E_{r,f} \to 0

(use d)). Now prove that the class τ(f)\tau(f) of Er,fE_{r,f} in R~C(C[T])\tilde{R}_C(C[T]) is independent of rr (≥deg⁡(f)\geq \deg(f)). (Indeed σr+sf=(σs1).(σrf)=Ts.(σrf)\sigma_{r+s} f = (\sigma_s 1).(\sigma_r f) = T^s.(\sigma_r f), and the class of the module C[T]/TsC[T]C[T]/T^s C[T] in R~C(C[T])\tilde{R}_C(C[T]) is zero.) Now prove that if gg is a polynomial in Λ(C)\Lambda(C), one has τ(fg)=τ(f)+τ(g)\tau(fg) = \tau(f) + \tau(g). (Use again the exact sequence (*).) Deduce from this that τ\tau extends to a group homomorphism

τ:Λrat(C)→R~C(C[T]). \tau : \Lambda_{rat}(C) \to \tilde{R}_C(C[T]) .

f) Now prove that χ‾∘τ\overline{\chi} \circ \tau is the identity mapping of Λrat(C)\Lambda_{rat}(C). (Use the fact that if f∈Λ(C)f \in \Lambda(C) is a polynomial of degree ≤r\leq r, then the characteristic polynomial of TEr,fT_{E_{r,f}} is σrf\sigma_r f.) g) Now prove that every element of R~C(C[T])\tilde{R}_C(C[T]) is the class of a C[T]C[T]-module E which is a free CC-module.

h) Let E be a C[T]-module, and denote by u∈EndC(E)u \in \mathrm{End}_C(E) the homothety of ratio T in E; let u‾=IdC[T]⊗Cu∈EndC[T](E[T])\overline{u} = \mathrm{Id}_{C[T]} \otimes_C u \in \mathrm{End}_{C[T]}(E[T]). We have an exact sequence of C[T]-modules

0⟶E[T]→T−u‾E[T]⟶E⟶0 0 \longrightarrow E[T] \xrightarrow{T-\overline{u}} E[T] \longrightarrow E \longrightarrow 0
(A, III, p. 106). Suppose that E is a free C-module with basis (e1,...,er)(e_1, ..., e_r). Then E[T] is a free C[T]-module with basis (1⊗ei)(1 \otimes e_i). If the matrix of uu for the basis (ei)(e_i) is (aij)(a_{ij}), the matrix of T−u‾T - \overline{u} for the basis (1⊗ei)(1 \otimes e_i) is (Tδij−aij)(T \delta_{ij} - a_{ij}).

i) Let f=(fij)1≤i,j≤rf = (f_{ij})_{1 \leq i,j \leq r} be a matrix with coefficients in C[T]. We shall say that ff is special if, whatever i,ji, j in {1,...,r}\{1, ..., r\}, i≠ji \neq j, fiif_{ii} is a monic polynomial and deg⁡(fii)>deg⁡(fij)\deg(f_{ii}) > \deg(f_{ij}). Now prove that det⁡(f)\det(f) is a monic polynomial (of degree deg⁡(f11)+⋯+deg⁡(frr)\deg(f_{11}) + \cdots + \deg(f_{rr})) and that ff defines an injective endomorphism of C[T]''. Deduce from h) that every C[T]-module which is a free C-module of rank rr is isomorphic to the cokernel of such an endomorphism of C[T]''.

j) Let ff be a special matrix as in i). Put f=(f11f+f−f′)f = \begin{pmatrix} f_{11} & f_+ \\ f_- & f' \end{pmatrix} where f+,f−,f′f_+, f_-, f' are matrices of types (1,r−1)(1, r-1), (r−1,1)(r-1, 1) and (r−1,r−1)(r-1, r-1) respectively. Put

g=(10−f−f11I)andh=gf=(f11f+0f‾) g = \begin{pmatrix} 1 & 0 \\ -f_- & f_{11} I \end{pmatrix} \quad \text{and} \quad h = gf = \begin{pmatrix} f_{11} & f_+ \\ 0 & \overline{f} \end{pmatrix}
where f‾=f11f′−f−f+\overline{f} = f_{11} f' - f_- f_+. Now prove that hh is a special matrix. Moreover, by identifying square matrices with the corresponding endomorphisms, one obtains exact sequences of C[T]-modules
0→Coker(f)→Coker(h)→Coker(g)→0, 0 \to \mathrm{Coker}(f) \to \mathrm{Coker}(h) \to \mathrm{Coker}(g) \to 0,
(where Coker(g)\mathrm{Coker}(g) is isomorphic to C[T]r/f11C[T]r−1\mathbf{C}[T]^r / f_{11} \mathbf{C}[T]^{r-1}) and
0→C[T]/f11C[T]→Coker(h)→Coker(f‾)→0. 0 \to \mathbf{C}[T]/f_{11} \mathbf{C}[T] \to \mathrm{Coker}(h) \to \mathrm{Coker}(\overline{f}) \to 0.
Deduce from this, by induction on rr, that Coker(f)\mathrm{Coker}(f) is a projective C-module whose class in RC(C[T])R_C(C[T]) is a Z\mathbf{Z}-linear combination of elements of the form [C[T]/pC[T]][C[T]/pC[T]] where pp is a monic polynomial.

k) Use the preceding parts f), g), i) and j) to show that τ:Λrat(C)→R~C(C[T])\tau : \Lambda_{rat}(C) \to \tilde{R}_C(C[T]) is surjective, hence that χ‾:R~C(C[T])→Λrat(C)\overline{\chi} : \tilde{R}_C(C[T]) \to \Lambda_{rat}(C) is an isomorphism.

l) Now prove that Λrat(C)\Lambda_{rat}(C) is stable by VnV_n and FnF_n for each n∈Jn \in J. There correspond therefore to them endomorphisms VnV_n and FnF_n of R~C(C[T])\tilde{R}_C(C[T]), by the preceding isomorphism. Let φn\varphi_n be the homomorphism of C-algebras of C[T] into itself which maps T onto TnT^n. Now prove that VnV_n (resp. FnF_n) is deduced from the endomorphism φn∗\varphi_n^* (resp. (φn)∗(\varphi_n)_*) of RC(C[T])R_C(C[T]) by passing to quotients.

In the exercises below, pp is a fixed prime number, and the Witt vector rings are relative to this prime number.

Solution

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.