Bourbaki

Exercise 15, § 3

Commutative Algebra, VII

Bourbaki marks this one as harder than the rest.

Let K be a complete field for a discrete valuation vv, A the ring of the valuation, k its residue field, P a polynomial of A[X1,…,Xn]A[X_1, \ldots, X_n] of total degree d having the following property: there exists an algebraic extension K′K' of K such that in K′[X1,…,Xn]K'[X_1, \ldots, X_n], P is a product of polynomials of total degree 1. Suppose moreover that there exist two polynomials Q, R of A[X1,…,Xn]A[X_1, \ldots, X_n] such that Q is of total degree s and contains a monomial aX1saX_1^s where φ(a)≠0\varphi(a) \neq 0 (φ\varphi denoting the canonical homomorphism A→kA \to k), that R is of degree ≤d−s\leq d - s, and that one has Pˉ=Qˉ⋅Rˉ\bar{P} = \bar{Q} \cdot \bar{R} (notations of Chapter III, § 4). Now prove that there then exist in A[X1,…,Xn]A[X_1, \ldots, X_n] two polynomials Q0,R0Q_0, R_0 of respective degrees s, d−sd - s, such that P=Q0R0P = Q_0 R_0, Qˉ=Qˉ0,Rˉ=Rˉ0\bar{Q} = \bar{Q}_0, \bar{R} = \bar{R}_0 and that Q0Q_0 contains a monomial a0X1sa_0 X_1^s with φ(a)=φ(a0)\varphi(a) = \varphi(a_0), (Consider P, Q, R as polynomials in X1X_1 with coefficients in the ring B, the completion of A[X2,…,Xn]A[X_2, \ldots, X_n] for the valuation obtained by extending vv according to the method of Chapter VI, § 10, No. 1, Prop. 2; then apply Hensel's lemma; finally use the initial assumption on P).

Solution

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Machine translation of the English, by gpt-5-6. Not checked by a person.