Bourbaki

Exercise 15, § 1

Commutative Algebra, VIII, p. 83

With the notation of the preceding exercise, suppose that the residue field and the field of fractions of the ring VV are isomorphic (this is the case, for example, when V=k[[U]]V = k[[U]], the field kk being the field of fractions of a ring of formal power series in an infinite number of indeterminates with coefficients in a field). Let σ\sigma be an isomorphism of V[T]/m1V[T]/m_1 onto V[T]/m2V[T]/m_2. Let C denote the subring of V[T]=EV[T] = E formed by the elements of E whose classes modulo m1m_1 and m2m_2 correspond under σ\sigma. Now prove that C is noetherian and that m1m2=m1∩m2m_1 m_2 = m_1 \cap m_2 is a maximal ideal of C. Now prove that E is the integral closure of C (note that E=C+C.(πT−1)E = C + C.(\pi T - 1) and that (πT−1)2+(πT−1)(\pi T - 1)^2 + (\pi T - 1) belongs to C).

Let A be the local ring Cm1m2C_{m_1 m_2}. Then A is integral and of dimension 2, hence catenary; the integral closure B=E⊗CAB = E \otimes_C A of A is a noetherian semilocal ring possessing exactly two maximal ideals n1n_1 and n2n_2, and we have dim⁡(Bn1)=1\dim(B_{n_1}) = 1, dim⁡(Bn2)=2\dim(B_{n_2}) = 2.

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Machine translation of the English, by gpt-5-6-mini. Not checked by a person. That model is a cut down version of the one the rest of this language was written by.